Answer:
Temperature of boiling point for solution is 101.60°C
Explanation:
This colligative property is boiling point elevation.
ΔT = Kb . m . i
ΔT = T° boiling point for solution - T° boiling point for pure solvent
Kb = The molal boiling point constant
m = molality
i = Van't Hoff factor ( for NaCl i = 2)
NaCl → Na⁺ + Cl⁻
Let's calculate molality (mol of solute in 1kg of solvent)
Mol of salt = Salt mass / Salt Molar mass
Mol of salt = 45 g / 58.45 g/m → 0.769 moles
0.769 moles/0.5 kg = 1.54 m
T° boiling point for solution - 100°C = 0.52°C/m . 1.54m . 2
T° boiling point for solution = (0.52°C/m . 1.54m . 2) + 100°C
T° boiling point for solution = 101.60°C