Question

How many ml of 12.0 M H2S04 are needed to make 500.0 ml of a 1.00 M solution? What happens to the freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it?

Answer 1

Answer:

41.66 mL of 12.0 M sulfuric acid are needed.

Explanation:

Concentration of sulfuric acid solution taken =$M_1=12.0M$

Volume of the 12.0 M Solution = $V_1$

Concentration of required solution = $M_2=1.00M$

Volume of required 1.00 M solution = $V_2=500.0 mL$

$M_1V_1=M_2V_2$ (Dilution)

$V_1=\frac{1.00 M\times 500.0 mL}{12.0 M}=41.66 mL$

41.66 mL of 12.0 M sulfuric acid are needed.

The freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it decrease and increase respectively.