The mass in grams of NH₃ produced from the reaction is 3.4 g
<h3>Balanced equation</h3>
We'll begin by writing the balanced equation for the reaction. This illustrated below:
N₂ + 3H₂ -> 2NH₃
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
<h3>How to determine the volume of NH₃ produced</h3>
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
Therefore,
2.24 dm³ of N₂ will react to produce = 2.24 × 2 = 4.48 dm³ of NH₃
<h3>How to determine the mass of NH₃ produced</h3>
We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:
22.4 dm³ = 1 mole NH₃
Therefore,
4.48 dm³ = 4.48 / 22.4
4.48 dm³ = 0.2 mole of NH₃
Finally, we shall determine the mass of NH₃ as follow:
- Molar mass of NH₃ = 17 g/mol
- Mole of NH₃ = 0.2 mole
- Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 0.2 × 17
Mass of NH₃ = 3.4 g
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Option B
dumbbell is the shape of 3p atomic orbital
<u>Explanation:</u>
Atomic orbitals are three-dimensional places inside an atom where there is a tremendous chance of detecting electrons. The p orbital, which develops in complexity and ought 2 spaces encompassing the atom core, or is defined as possessing a dumbbell pattern. The 3p atomic orbital is at energy level 3, as seen by the number 3 filed ere the character.
These orbitals have identical appearances but are arranged asymmetrically in location. p orbitals are wavefunctions with l=1. They ought an angular frequency that is ununiform at each angle. They have an appearance that is much defined as a "dumbbell".
Answer:
Molarity of Na₂CO₃ = 0.25M
% mass = 2.69
Explanation:
Molarity means mole of solute in 1L of solution
Molar mass of solute (Na₂CO₃) = 105,98 g/m
Moles = mass / molar mass → 6.73 g / 105.98 g/m = 0.0635 m
Mol/L = [M]
0.0635 mol/0.250L = 0.25M
Density of solution = Solution mass / Solution volume
1 g/ml = Solution mass / 250 mL → Solution mass is 250g
% mass will be:
In 250 g of solution we have 6.73 g of solute
in 100 g of solution we have (100 . 6.73)/250 = 2.69
3.6 x 10²³
Explanation:
Given parameters:
Number of cell per body = 60 trillion body cells
Population of the earth = 6 billion
Unknown:
Total number of living human body cells = ?
Solution:
To solve this problem, simply find the product:
Total number of living human body cells = number of cell per body x population of the earth
1 trillion = 1 x 10¹²
60 trillion = 6 x 10¹³
1 billion = 1 x 10⁹
6 billion = 6 x 10⁹
Total number of living human body cells = 6 x 10¹³ x 6 x 10⁹
= 6 x 6 x 10⁽¹³⁺⁹⁾
= 36 x 10²² or 3.6 x 10²³
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First, take the molar mass of B (10.81g) and divide the value you've been given by the molar mass to get moles (5.4 / 10.81). So you have .5 moles of B and then you need to convert that to atoms. To do that you must use the constant 6.022X10^23 atoms per mole. Take your moles and multiply it by that constant. Your final answer should be (3.01X10^23) atoms.
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