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djverab [1.8K]
3 years ago
7

0.21 divided by 0.0966

Mathematics
1 answer:
NARA [144]3 years ago
5 0

Answer:

2.173913043478261

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4 0
3 years ago
Suppose the number of hits a webpage receives follows a Poisson distribution. The average number of hits per minute is 2.4. What
REY [17]

Answer:

The probability that the page will get at least one hit during any given minute is 0.9093.

Step-by-step explanation:

Let <em>X</em> = number of hits a web page receives per minute.

The random variable <em>X</em> follows a Poisson distribution with parameter,

<em>λ</em> = 2.4.

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

Compute the probability that the page will get at least one hit during any given minute as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-\frac{e^{-2.4}(2.4)^{0}}{0!}\\=1-\frac{0.09072\times1}{1} \\=1-0.09072\\=0.90928\\\approx0.9093

Thus, the probability that the page will get at least one hit during any given minute is 0.9093.

6 0
3 years ago
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