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katrin2010 [14]

3 years ago

15

10

1 answer:

sergejj [24]3 years ago

8 0

The answer is C.

Explanation:

If you were to buy 5 games and they all cost $69.99 and you want to know to total cost, you would do $69.99 x 5 or count $69.99 five times.

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Write a single transformation that maps ABC onto A' B' C'

blsea [12.9K]

9514 1404 393

Answer:

Either of ...

(x, y) ⇒ (-x, -y)
Rotation 180° about the origin

Step-by-step explanation:

There are at least two ways to express the transformation that maps each coordinate to its opposite.

1. reflection across the origin: (x, y) ⇒ (-x,-y)

2. rotation 180° (either direction) about the origin.

Take your pick.

4 0

4 years ago

Please please please I beg someone please help me with this!!!!!!!!!!!!

alexdok [17]

Look at my attachment to see the four functions on the graph.

f --> g . . . . . shift the graph down one unit

f --> h . . . . . shift down 2 units, and double the slope

f --> d . . . . . shift up 2 units, and reduce the slope by half

3 0

3 years ago

Please please help it is very urgent!

Liula [17]

Y = -0.33x + -5.00 (rounded to the nearest 100)

7 0

3 years ago

The drama club has $4000 to spend on their winter performance. They have already

disa [49]

Answer:

The drama club can purchase 1429 programs

Step-by-step explanation:

4 0

3 years ago

4(3x^2y^4)^3 / (2x^3y^5)^4

tatyana61 [14]

Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to Solve the expression: $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}$

Another exponent rule says: $x^{-a}=\frac{1}{x^a}=$

$=\frac{27}{4x^{6}y^{8}}$

So, solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

8 0

3 years ago