X=?
Well this is very complicated my child.
-SC
Answer:
D it will remain at rest
Step-by-step explanation:
Balanced force is two forces pushing the same amount on different sides of an object. If you and a friend tried pushing a table from either side with the same amount of force, it wouldn’t move.
The period is 7 because period = 2pi/b for asin(b(x-h))+k, so period is 2pi/(2pi/7) = 7
Answer:
(5,19) lies on the graph of the transformed function y = f(1/5x)
Step-by-step explanation:
Suppose (1,19) is on the graph of y = f (x)
the graph of the transformed function y = f(1/5x)
![y=f(\frac{1}{5}x)](https://tex.z-dn.net/?f=y%3Df%28%5Cfrac%7B1%7D%7B5%7Dx%29)
1/5 is multiplied with x in f(x)
1/5 is less than 1 so there will be a horizontal stretch in the graph by the factor of 1/5
To make horizontal stretch we change the point
f(x)=f(bx) then (x,y) --->( x/b,y)
We divide the x coordinate by the fraction 1/5
(1,19) ----> ![(\frac{1}{\frac{1}{5}} , 19)= (5,19)](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B%5Cfrac%7B1%7D%7B5%7D%7D%20%2C%2019%29%3D%20%285%2C19%29)
So (5,19) lies on the graph of the transformed function y = f(1/5x)
To express the value of the arc secant of the square root of 2 you must first express its cross multiplication process that having variable x as its total then you will came up with sec(x) =sqrt(2) then remember that sec() is equals to 1/cos(x), then its is 1/cos(x) = sqrt(2) then use the special triangle principles withe side length of 1,1 and sqrt(2) and the value of that is pi/4 so x= pi/4 then arcsec(sqrt(2)) = pi/4.