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4 years ago

8

Me pueden ayudar con este ejercicio por favor, explicado paso por paso Tipo de ejercicios 1 – Integración por sustitución. Desar

rollar los ejercicios seleccionado utilizando el método de integración por sustitución.

1 answer:

Anton [14]4 years ago

6 0

Answer:

where is the question I want to help you.

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Show that if A is invertible, then det Upper A Superscript negative 1det A−1equals=StartFraction 1 Over det Upper A EndFraction

netineya [11]

Answer:

Therefore

$det(A)*det(A^{-1}) = 1$ and $det(A^{-1}) = 1/det(A)$

Step-by-step explanation:

Remember that if

$I$ = Identity Matrix

then $det(I)=1$ .

Also remember that for any invertible matrix

$A*A^{-1} = I =$ Identity Matrix.

Therefore

$det(A*A^{-1}) = det(A)*det(A^{-1}) = det(I) = 1$

Therefore

$det(A)*det(A^{-1}) = 1$ and $det(A^{-1}) = 1/det(A)$

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3 years ago

ada recorded the thickness a of a set of books. This line plot shows her results. Jada stacked the books that were 112 inches th

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3 years ago

kirza4 [7]

Answer:

12+k/5

Quotient is a quantity produced by the division of two numbers.

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3 years ago

Simplify the radical expression.

Fofino [41]

B. 10 square root 5
hope this helps:)
pls mark thanks and brainliest:)

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3 years ago

What is the value of y?<br> у<br> 60°<br> 80°

Marina86 [1]

Answer: 40

Step-by-step explanation:

The angles form a straight angle, so y = 180 - 80 - 60 = 40.

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2 years ago