First step, expand the left side (multiply together) (apply FOIL/distribution property)
2nd step, solve so that one side is zero, by adding/subtracting like terms
3rd step, solve for x
Answer:
The population of deer at any given time = 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Step-by-step explanation:
This is an example of logistic equation on population growth
carrying capacity, k = 200
Rate, r = 3% = 0.03
Initial Population, P1 = 80
P(t) =?
P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))
P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))
= (16000(e^0.03t)) ÷ (120 + 80(e^0.03t))
= 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Answer:40
step by step explanation
3*23÷46=6
46-6=40
there are 40 pies in each plate
Given:
A square base pyramid whose base length is 10 in. and height of triangular surface is 4 in.
To find:
The surface area of the pyramid to the nearest whole number.
Solution:
A square base pyramid contains square base with edge 10 in. and 4 congruent triangles with base 10 in. and height 4 in.
Area of a square is
So, area of square base is 100 sq. in.
Area of a triangle is
So, area of each triangular surface is 20 sq. in.
Now, the total surface area of the pyramid is
Total area = Area of square base + Area of 4 congruent triangles.
Therefore, the area of the pyramid is 180 sq. in.
Answer:
The range of the function is the set of all possible values that function can take. Both given functions
y=\left(\dfrac{4}{5}\right)^xy=(
5
4
)
x
and y=\left(\dfrac{4}{5}\right)^x+6y=(
5
4
)
x
+6
are exponential functions with base \dfrac{4}{5}.
5
4
.
The graphs of these function you can see in attached diagram.
The range of the function y=\left(\dfrac{4}{5}\right)^xy=(
5
4
)
x
is (0,\infty).(0,∞).
The range of the function y=\left(\dfrac{4}{5}\right)^x+6y=(
5
4
)
x
+6 (this function is translated function y=\left(\dfrac{4}{5}\right)^xy=(
5
4
)
x
6 units up) is (6,\infty).(6,∞).
