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valentinak56 [21]
3 years ago
14

Slope of (-2,-3) and (6,2)

Mathematics
1 answer:
alexira [117]3 years ago
4 0
\frac{5}{8} is the slope between these two points. 

To figure out the slope between two points, we need to find the rise over run, which is the change in the <em>y value over the change in the x value</em>. This becomes:

\frac{2 - (-3)}{6 - (-2)}

And simplifies to:
\frac{5}{8}, meaning that the slope between these two points is \frac{5}{8}.
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2 years ago
2.<br> What is the next term of the arithmetic sequence 6, 10, 14, 18, ...?
riadik2000 [5.3K]

Answer:

22

Step-by-step explanation:

In this sequence, the next number is found by adding 4.

4 0
3 years ago
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Consider the set T = {1, 2, 3, 4, 5, 6}. Let R = {(a, b) | a divides b} be a relation on the set T. Identify the missing ordered
serg [7]

Answer:  The missing ordered pairs are  (2, 2), (2, 4), (2, 6), (3, 3) and (3, 6).

Step-by-step explanation:  We are given the following set :

T = {1, 2, 3, 4, 5, 6}.

And, R = {(a, b) | a divides b} be a relation on the set T.

We are to identify the missing pairs from the following list of all ordered pairs in the given relation R on the set T :

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), _____, (4, 4), (5, 5), and (6, 6).}.

Since R contains the ordered pairs (a, b) such that a divides b, so all the ordered pairs in R are

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 2), (2, 4), (2, 6), (3, 3), (3, 6), (4, 4), (5, 5), and (6, 6).

Thus, the missing ordered pairs are  (2, 2), (2, 4), (2, 6), (3, 3) and (3, 6).

4 0
3 years ago
How much heat is released when 12. 0 grams of helium gas condense at 2. 17 K? The latent heat of vaporization of helium is 21 J/
aleksandr82 [10.1K]

The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J

The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.

However, since we are required to determine heat released when the helium gas condenses.

The heat of condensation per gram is; -21 J/g.

Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.

Approximately, -250J.

Read more on latent heat:

brainly.com/question/19863536

7 0
2 years ago
Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).
weeeeeb [17]

Answer:

\[y = (-1/2) * x + 6\]

Step-by-step explanation:

Equation of the given line: y=2x+2

Hence the slope of the line is given by 2

Any line which is perpendicular to the given line will have a slope m such that m*2 = -1

Or, \[m = \frac{-1}{2}\]

Only options 2 and 3 satisfy this condition.

The line is also supposed to pass through the point (6,3).

Substituting these values in the option 2:

\[3 = (-1/2) * 6 + 3\]

Or, \[ 3 =0 \] which is false . Hence option 2 is not valid.

Now substituting (6,3) in option 3:

\[3 = (-1/2) * 6 + 6\]

Or, \[ 3 =3 \] which is true . Hence option 3 is the required equation of the line.

5 0
3 years ago
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