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2 years ago

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Michael is paid $9 per hour to work at the movie theater and $7 per hour when he helps his aunt at her bakery. Michael cannot wo

rk more than 32 hours in a week, but he wishes to earn at least $251 each week. Which work schedule is within Michael’s constraints?

2 answers:

evablogger [386]2 years ago

4 0

if he works at the theater he can make $288 in 32 hours, if he works at his aunts he can make $224 in 32 hours. he should work at the theater to meet his goal.

I really hope this helps

Vladimir [108]2 years ago

4 0

Answer: It's c.) 19 hours at the movie theater and 12 hours at the bakery.

Step-by-step explanation:

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The radius of circle A is three feet less than twice the diameter of circle B. If the sun mmm of the diameters of both circles i

yanalaym [24]

Answer:

Area of Circle A = 1133.54

Circumference of Circle A= 119.32

Step-by-step explanation:

Given: Sum of both circle diameters= 49 feet.

Circle A radius= Three feet less than twice the diameter of circle B.

Lets assume diameter of Circle B is "x"

∴ Circle A radius (r)= $(2x-3)$

We know, the diameter of circle is $2r$

Diameter of Circle A is $2\times (2x-3)$

Next as given sum of both circle diameter is 49 feet.

∴ $2(2x-3)+x= 49\ feet$

distributing 2 with 2x and -3

⇒ $4x-6+x= 49$

⇒ $5x-6= 49$

Adding both side by 6

⇒ $5x=55$

Cross multiplying both side.

⇒ $x=\frac{55}{5} = 11$

∴ Diameter of circle B is 11 feet.

Next, subtituting the value of x to get the value of radius for Circle A.

Radius of circle A= $(2x-3)$

⇒ Radius of circle A= $(2\times 11-3)= 22-3$

∴ Radius of circle A= 19 feet.

Area of circle= $\pi r^{2}$

Taking π= 3.14

Area of circle A= $3.14\times 19^{2} = 3.14\times 361$

∴ Area of circle A= 1133.54

Circumference of circle= 2πr

Circumference of Circle A= $2\times 3.14\times 19= 119.32$

∴ Circumference of Circle A= 119.32

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3 years ago

Read 2 more answers

Find the measure of HIW in picture.

Contact [7]

10x+2x+13=145
angle of WIJ and HIW is equal to 145 degrees
12x+13=145
12x=132
x=11
angle of WIJ is 10x
angle of HIW is 2x+13
to find angle of HIW, you plug in x=11 into 2x+13 and
the answer and angle of HIW is 35 degrees.

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3 years ago

Hi I need this question please asap.

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Ike Jehoshaphat isn’t oso los

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3 years ago

A pendant is formed using a cylinder and cone. Once assembled, as shown below, the pendant is painted. How many square millimete

solmaris [256]

Surface area of cylinder is given by area of circle + area of the rectangle that curved around the cylinder

Area of the base of the cylinder = $\pi r^{2} = 8^{2} \pi =64 \pi$
Area of the cylinder 'wall' = width × length = $12$ × $2r \pi$ = $12$ × $16 \pi$ = $192 \pi$

Note that the wall of the cylinder is in the shape of a rectangle. The width of the rectangle is the height of the cylinder. The length of the rectangle is the circumference of the circle base.

Surface area of cone is given by $\pirl$ where $l$ is the slanted height of the cone

SA of cone = $\pi (8)(10)=80 \pi$

Hence total painted surface area is $80 \pi +192 \pi +64 \pi =336 \pi$

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3 years ago

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Experian would like to test the hypothesis that the average credit score for an adult in Virginia is different from the average

aliya0001 [1]

Answer:

a. We fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

b. The 95% confidence interval for the true difference of means is -2.2468 and 36.2468. There is a probability of 95% that the true difference of means $\mu_{1}-\mu_{2}$ is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

Step-by-step explanation:

Let $\mu_{1}-\mu_{2}$ be the true difference between the average credit score for an adult in Virginia and the average credit score for an adult in North Carolina. We have the large sample sizes $n_{1} = 40$ and $n_{2} = 35$ , the unbiased point estimate for $\mu_{1}-\mu_{2}$ is $\bar{x}_{1} - \bar{x}_{2}$ , i.e., 699-682 = 17.

The standard error is given by $\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$ , i.e.,

$\sqrt{\frac{(44)^{2}}{40}+\frac{(41)^{2}}{35}}$ = 9.8198.

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative). The rejection region is given by RR = {z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles of the standard normal distribution respectively. The test statistic is $Z = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}}$ and the observed value is $z_{0} = \frac{17}{9.8198} = 1.7312$ . Because 1.7312 does not fall inside RR, we fail to reject the null hypothesis.

b. The endpoints for a 95% confidence interval for $\mu_{1}-\mu_{2}$ is given by $17\pm (z_{0.05/2})9.8198$ , i.e., $17\pm (z_{0.025})9.8198$ where $z_{0.025}$ is the 2.5th quantile of the standard normal distribution, i.e., -1.96, so, we have 17-(1.96)(9.8198) and 17+(1.96)(9.8198), i.e., -2.2468 and 36.2468. There is a probability of 95% that the true difference of means $\mu_{1}-\mu_{2}$ is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

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