All categories

2 years ago

Help me please show how you got the answer

Mathematics

1 answer:

Lilit [14]2 years ago

3 0

Answer:

Firstly you need to put the equation in form of. y =ax+b

Let us do it

We have

2x-2y=18

-2y=18-2x

-y=(18) /2 - (2x)/2

-y =9-x

Mutiply by - to remove it beside y

Y=-9+x

Which is y=x-9

Slope =a=1

Yintercept=b=-9

You might be interested in

Find the missing probability. P(A)=13/20,P(A∩B)=13/25,P(B|A)=?

Tju [1.3M]

By definition of conditional probability,

P(B | A) = P(A ∩ B)/P(A) = (13/25) / (13/20) = 20/25 = 4/5

4 0

3 years ago

It's due in 30 minutes!!

Dominik [7]

Answer:

14 cups = 7 pints

144 cups = 36 quarts

Step-by-step explanation:

4 0

3 years ago

The sum of three integers is 12

Liula [17]

The three integers are 5,17 and -10

Step-by-step explanation:

Let x, y and z be three integers then

$x+y+z=12 \ \ \Eqn\ 1$

'The sum of the first and second integers exceeds the third by 32'

$x+y=z+32\ \ \ \ Eqn\ 2$

The third integer is 15 less than the first.

$z=x-15\ \ \ \ Eqn\ 3$

From Eqn 2:

$x+y=z + 32\\x+y-z=32$

Subtracting Eqn 1 from eqn 2

$x+y-z-(x+y+z)=32-12\\x+y-z-x-y-z=20\\-2z=20$

Dividing both sides by -2

$\frac{-2z}{-2}=\frac{20}{-2}\\z=-10$

Putting z=-10 in Eqn 3

$z=x-15\\-10=x-15\\x=15-10\\x=5$

Putting x=5 and z=-10 in Eqn 1

$x+y+z=12\\5+y-10=12\\y-5=12\\y=12+5\\y=17\\$

Hence,

The three integers are 5,17 and -10

Keywords: Linear Equations, Variables

Learn more about linear equations at:

#LearnwithBrainly

3 0

3 years ago

Read 2 more answers

What is 45 percent of 37? 0.1665 1.665 16.65 166.5

xxTIMURxx [149]

Answer:

16.65

Step-by-step explanation:

37 * 0.45 = 16.65

3 0

3 years ago

Read 2 more answers

HELP! WILL GIVE BRAINLEST! What is the approximate degree measure of an angle of 4.59 rad?

Lelechka [254]

Approximately 263 degrees or C

7 0

2 years ago

Read 2 more answers