Ryan has a $500 bond with a 6.5% coupon. How much interest will Ryan

To pass this year’s math class, Miriam needs to earn at least an 82%. Write an inequality that shows the scores Miriam could get

Gala2k [10]

Answer:

2

She has to believe in herself so she would ace that test

3 0

3 years ago

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A 500-page book contains 250 sheets of paper. The thickness of the paper used to manufacture the book has mean 0.08 mm and stand

LenaWriter [7]

Answer:

10.20% probability that a randomly chosen book is more than 20.2 mm thick

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.

So for the book.

$\mu = 250*0.08 = 20, \sigma = \sqrt{250}*0.01 = 0.158$

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)

This is 1 subtracted by the pvalue of Z when X = 20.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20.2 - 20}{0.158}$

$Z = 1.27$

$Z = 1.27$ has a pvalue of 0.8980

1 - 0.8980 = 0.1020

10.20% probability that a randomly chosen book is more than 20.2 mm thick

7 0

4 years ago

John is 3 years older than Jim. Jim is 4 years less than twice David’s age. How old are the three boys if their ages add up to 3

gulaghasi [49]

Answer:

15 years , 12 years , 8 years.

Step-by-step explanation:

Given:

John is 3 years older than Jim.

Jim is 4 years less than twice David’s age.

Ages of three boys add up to 35.

Question asked:

How old are the three boys?

Solution:

Let age of David = $y$

Let age of Jim = $x$

Then age of John will be = $x + 3$

As Jim is 4 years less than twice David’s age

Equation will be , $x = 2y - 4$

Multiplying both side by 2

= $2x = 4y - 8$ (let equation 1 )

As ages of three boys add up to 35.

Equation will be, $x + (x + 3) + y = 35$

= $2x + 3 + y = 35$

Subtracting both side by 3

= $2x + y = 32$

= $2x = - y + 32$ (let equation 2 )

subtracting equation 1 and 2,we get

= $2x = - y + 32$

= $2x = 4y - 8$

= $0 = - 5y + 40$

= $5y = 40$

dividing both side by 5

$= y = 8$ (David ages)

Then ( age of Jim) $x = 2y - 4$

$x = 2 \times8 - 4$

= $16 - 4$

= $12 years$

Then age of John will be, $x + 3$

$= 12 + 3$

= $15 years$

Thus, age of John = 15 years

Age of Jim = 12 years

Age of David = 8 years

7 0

3 years ago

Please help me I would really appreciate it.

Karo-lina-s [1.5K]

Given:

$\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}$

To prove:

$\Delta CDA\cong \Delta ABC$

Proof:

In $\Delta CDA\text{ and } \Delta ABC$ ,

$\overline{AB}\cong \overline {CD}$ because Given

$\overline{BC}\cong \overline {DA}$ because Given

$\overline{AC}\cong \overline {AC}$ because Reflexive property.

Corresponding sides of both triangles are congruent. So,

$\Delta CDA\cong \Delta ABC$ because SSS

Therefore, the required missing values are: Given, $\overline{BC}\cong \overline {DA}$ , Reflexive property , $\Delta CDA\cong \Delta ABC$ , SSS respectively.

5 0

3 years ago

Which of the following points is the solution of the inequality <br><img src="https://tex.z-dn.net/?f=y%20%3C%20%20-%20%20%7Cx%7

Harman [31]

Answer:

(1,0)

Step-by-step explanation:

Absolute value is represented by using these bars → ║.

║= number of units from 0.

This equation says that whatever number is in the absolute value bars , x , is greater than y.

4 0

3 years ago

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