Answer: a,c,f (4^3, 8^2, 2^6)
Step-by-step explanation:
Answer:
For f(x) to be differentiable at 2, k = 5.
Step-by-step explanation:
For f(x) to be differentiable at x = 2, f(x) has to be continuous at 2.
For f(x) to be continuous at 2, the limit of f(2 – h) = f(2) = f(2 + h) as h tends to 0.
Now,
f(2 – h) = 2(2 – h) + 1 = 4 – 2h + 1 = 5 – 2h.
As h tends to 0, lim (5 – 2h) = 5
Also
f(2 + h) = 3(2 + h) – 1 = 6 + 3h – 1 = 5 + 3h
As h tends to 0, lim (5 + 3h) = 5.
So, for f(2) to be continuous k = 5
So 7 friends with similar. Phone plans. 3 of them pays an extra 4 bucks, so that means that x+ 4 is what 3 of the 7 r paying. The other 4 pay just x Amt of money for their plan. So go find the total bill, it would be (x+4)+(x+4)+(x+4)+x+x+x+x. Now simplify, (x+4)^3, because there are three of the 7 using that, and then x^4, because 4 of the 7 r using that plan. So in total it would be (x+4)^3+ x^4. Hope this helps
Answer:
26,000,000 codes
Step-by-step explanation:
To find how many unique codes can be created, we just need to check how many possibilities there are for each letter or digit in the code.
Each letter has 26 possible values, and each digit has 10 possible values, so as we have 1 letter and 6 digits, the total number of unique codes are:
26 * 10 * 10 * 10 * 10 * 10 * 10 = 26,000,000 codes.
