Genetic Inheritance: Calculate probability of two children having the same genotype for achrondoplasia Achondroplasia is a commo
n form of dwarfism caused by autosomal dominant mutation in the fibroblast growth factor receptor 3 (Fgfr3) gene. If a person with achondroplasia (Aa) married and had children with a person of normal height, what is the probability that both their first child and second child would have achondroplasia?
The correct answer is - 1/2 or 50% for first and second child to be affected.
Step-by-step explanation:
Achondroplasia is an autosomal dominant disorder. Autosomal dominant disorder refers to the presence of a single copy of the defective gene that is enough to lead to dwarfness.
A cross of achondroplasia (Aa) parent to a person of normal height (aa) result in half of their children will be affected with dwarfism and the other half will be normal.
a cross between affected or dwarf and normal parent
Aa X aa
Punnett square:
a a
A Aa Aa
a aa aa
Aa- dwarfness
aa- normal height
The probability that both their first child and second child would have achondroplasia is
For this case we have the following equation: P (t) = P (1 + r / n) ^ (n * t) Where, P: initial investment r: interest n: periods t: time she will take on her 45th birthday: for t = 25: P (25) = 1000 * (1 + 0.0165 / 4) ^ (4 * 25) P (25) = 1509.31 $ Answer: The future value of this investment when she takes her trip is: P (25) = 1509.31 $
