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Andreyy89
3 years ago
11

Genetic Inheritance: Calculate probability of two children having the same genotype for achrondoplasia Achondroplasia is a commo

n form of dwarfism caused by autosomal dominant mutation in the fibroblast growth factor receptor 3 (Fgfr3) gene. If a person with achondroplasia (Aa) married and had children with a person of normal height, what is the probability that both their first child and second child would have achondroplasia?
Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

Answer:

The correct answer is - 1/2 or 50% for first and second child to be affected.

Step-by-step explanation:

Achondroplasia is an autosomal dominant disorder. Autosomal dominant disorder refers to the presence of a single copy of the defective gene that is enough to lead to dwarfness.

A cross of achondroplasia (Aa) parent to a person of normal height (aa) result in half of their children will be affected with dwarfism and the other half will be normal.

a  cross between affected or dwarf  and normal parent

     Aa X aa

Punnett square:

         a a

A  Aa Aa

a aa aa

Aa- dwarfness

aa- normal height

The probability that both their first child and second child would have achondroplasia is

2/4 =1/2 or 50%.

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In other words, it's the second answer choice

===========================================================

Explanation:

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3 0
3 years ago
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Step-by-step explanation:

This is the slope intercept form of a line.  

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2 years ago
(8/9)^-2 without an exponent
Ganezh [65]

Answer:

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3 years ago
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Step-by-step explanation:

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