Does anyone know how to do this

Write the equation of the ellipse graphed below.

Lana71 [14]

Answer:

Step-by-step explanation:

This is a horizontally stretched ellipse. That means that the horizontal line which is represented by the x-axis is the longer one. The equation for this type of ellipse is

$\frac{(x-h)^2}{a^2} +\frac{(y-k)^2}{b^2} =1$

In an ellipse, the a value is ALWAYS bigger than the b value, and since the x-axis represents the longer axis, the a goes under the x-squared term.

To solve for the h, the k, the a, and the b, we simply have to do some counting. The center of the ellipse, the (h, k) our of equation, is sitting at (4, 6). Put them where they belong in the equation. The a axis (the horizontal one) is 8 units long, and the b axis (the vertical one) is 4 units long. Square both of them and put them where they belong in the equation:

$\frac{(x-4)^2}{64}+\frac{(y-6)^2}{16} =1$

There you go!

8 0

3 years ago

Find the area of the triangle.

ira [324]

Wait is this geometry?

5 0

3 years ago

Leila has scored 33, 28, 24 and points in her three basketball games so far. How many points does she need to score in her next

zubka84 [21]

ANSWER:

24 points.

The amount of points Leila needs to score in her next game so that her average is 27 points per game is: 24 points.

STEP-BY-STEP EXPLANATION:

Let the amount of points Leila needs to score in her next game so that her average is 27 points per game = x

27 = total no. of points / total no. of games

27 = ( 33 + 28 + 24 + x ) / ( 3 + 1 )

27 = ( 85 + x ) / 4

27 × 4 = 85 + x

85 + x = 108

x = 108 - 85

x = 24

5 0

3 years ago

Round 100.9052 to the nearest hundredths

Bas_tet [7]

To round 100.952 to the nearest tenth consider the hundredths’ value of 100.952, which is 5 and equal or more than 5. Therefore, the tenths value of 100.952 increases by 1 to 0.

100.952 rounded to the nearest tenth = 101.0

6 0

2 years ago

Please help! Help me with the steps as well not just answers:/

serious [3.7K]

For question 1 you need to find the sqared values of the hypotenuse, which has a length of 15, and leg b, which has a length of 12. This gives you a hypotenuse of 225 and a leg which is 144. Subtract your given leg squared from your hypotenuse squared (aka 225-144). This leaves you with 81. Now find the square root of this, which is 9.

For question 2 you need to find the squared value of legs a and b. Leg a has an initial length of 6, which squared is 36. The same applies for leg b. Now add 36 to 36 to get 72. All you have to do is find the square root of that to have your answer. Since 72 isn't a perfect square, just simplify the root to 3 root 8, aka
$3 \sqrt{8}$
For question 3, repeat the process used in question 1. The square of a square root is the original number (ex: the sqare root of 3 squared is 3). Subtract 7 from 19 to get 12. 12 isn't a perfect square, so simplify the root. You should end up with 2 root 3, aka
$2 \sqrt{3}$

For question 4 you must find the sqared value of a, b, and c. The sum of the sqared values of a and b is equal to the squared value of c. If c is 10 and a and b are both x, then the formula is
${x}^{2} + {x}^{2} = 100$
or
$2 {x}^{2} = 100$
Next, simplify this by first dividing by 2 on each side. You are then left with x squared equals 50. Simplify the root to 5 root 2, aka
$5 \sqrt{2}$

For question 5 you need to find the squared value of 47 and 25. This leaves you a hypotenuse of 2209 and a width of 625. Subtract 625 from 2209. This leaves you with 1584. Find the sqare root of this to find your length. Since it isn't a perfect square, simplify the root to get 12 root 11, aka
$12 \sqrt{11}$

I hope this helps clear things up for you!

3 0

3 years ago