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andrezito [222]

3 years ago

8

Given: MNFD is a trapezoid.

1 answer:

Rama09 [41]3 years ago

6 0

A trapezoid with legs MN = FD is an isosceles trapezoid.
An isosceles trapezoid has diagonals that are congruent, therefore: MF = ND.
A quadrilateral with diagonals congruent and perpendicular is a square.
In a square, the height coincides with the side.
The area of a square is given by A = s²
Therefore, the area of MNFD is h²

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Solve for x.<br><br> log x + log 3 = log 18<br><br> Enter your answer in the box.

Makovka662 [10]

log(x) + log(3) = log(18)

log(x) + 0.477121 = 1.255273

Add -0.477121 to both sides.

log(x) + 0.477121 + −0.477121 = 1.255273 + −0.477121

log(x)+0 = 0.778152

Divide both sides by 1.

log(x)+0/1 = 0.778152/1

log(x)=0.778152

Solve Logarithm

log(x) = 0.778152

10log(x) = 100.778152

x = 100.778152

x = 6.00001

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3 years ago

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What is the area of the composite figure shown.

AlekseyPX

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Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.

natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is $y=x-x^2-2$ and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

$y'=1-2x$

It can be written as

$\frac{dy}{dx}=1-2x$

Use variable separable method to solve this differential equation.

$dy=(1-2x)dx$

Integrate both the sides.

$\int dy=\int (1-2x)dx$

$y=x-2(\frac{x^2}{2})+C$ $[\because \int x^n=\frac{x^{n+1}}{n+1}]$

$y=x-x^2+C$ ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

$-2=1-(1)^2+C$

$-2=1-1+C$

$-2=C$

The value of C is -2. Substitute C=-2 in equation (1).

$y=x-x^2-2$

Therefore the solution of the given initial value problems in explicit form is $y=x-x^2-2$ .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

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HACTEHA [7]

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Answer:

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Step-by-step explanation:

multiply each term in parenthesis by 4.

multiply the numbers <u>4×7</u>+4v

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