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saul85 [17]
3 years ago
5

Can you please help me with this math problem

Mathematics
2 answers:
JulijaS [17]3 years ago
5 0

This question is nasty. It sounds like you should be finding area of the figure you see. I'll do that first, although I don't think it's the right answer. (But it might be).


Area Trapezoid = (b1 + b2) * h / 2

b1 = 8

b2 = 12

h = 5

Area Trapezoid = (8 + 12 ) * 5 / 2

Area Trapezoid = 20 * 5/2

Area = 50 square feet.


The problem is that no lumber yard will cut that for you without charging you. The practical answer is 12 * 5  = 60 square feet is what you will have to buy. Then you cut out the triangles for yourself.



Lera25 [3.4K]3 years ago
3 0
This question is nasty. It sounds like you should be finding area of the figure you see. I'll do that first, although I don't think it's the right answer. (But it might be).

Area Trapezoid = (b1 + b2) * h / 2
b1 = 8
b2 = 12
h = 5
Area Trapezoid = (8 + 12 ) * 5 / 2
Area Trapezoid = 20 * 5/2
Area = 50 square feet.

The problem is that no lumber yard will cut that for you without charging you. The practical answer is 12 * 5  = 60 square feet is what you will have to buy. Then you cut out the triangles for yourself.
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Option (2)

Step-by-step explanation:

Measure of angle formed by two tangents from a point outside the circleis half the difference of the measures of the intercepted arcs.

From the figure attached,

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Your answer:
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