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yuradex [85]
3 years ago
7

A helical compression spring is to be made of oil-tempered wire, d, of diameter 1–mm with a spring index of C = 10. The spring i

s to operate inside a hole, so buckling is not a problem and the ends can be left plain. The free length of the spring, Lo, should be 86 mm. A force of 50 N should deflect the spring 15 mm.
Engineering
1 answer:
BaLLatris [955]3 years ago
5 0

Question

Determine the minimum hole diameter for the spring to operate in

Answer:

11 mm

Explanation:

Mean spring coil diameter is given from the following relationship

D=cd where C is spring index and d is the diameter of oil-tempered wire

By substitution

D=10*1 mm=10 mm

To find the outer diameter, we add the d to D hence getting the minimum hole diameter as

D_o= D+d= 10 mm+1 mm= 11 mm

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An elastic cable is to be designed for bungee jumping from a tower 130 ft high. The specifications call for the cable to be 85 f
azamat

Answer:

<em>a) The spring constant is 50 lb/ft</em>

<em>b) The man is 26.3 ft close to the ground.</em>

<em></em>

Explanation:

Height of tower is 130 ft

Specification calls for a cable of length 85 ft

the maximum this length stretches is 100 ft when subjected to a load of 750 lb

The extension of the cable is calculated from the formula from Hooke's law

F = kx

where F is the load or force on the cable

k is the spring constant of the cable

x is the extension on the cable

a) The extension on the cable is

x = 100 ft - 85 ft = 15 ft

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