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pickupchik [31]
3 years ago
11

Tech A says you can find the typical angle of a V-block engine by dividing the number of cylinders by 720

Engineering
1 answer:
Lady_Fox [76]3 years ago
8 0

Answer:

Tech A is correct

Explanation:

Tech A is right as its V- angle is identified by splitting the No by 720 °. Of the piston at the edge of the piston.

Tech B is incorrect, as the V-Angle will be 720/10 = 72 for the V-10 motor, and he says 60 °.

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Tungsten is being used at half its melting point (Tm≈3,400◦C) and astress level of 160 MPa. An engineer suggests increasing the
Paladinen [302]

Answer:

Explanation:

The missing diagram is attached in the image below which shows the deformation map of the Tungsten.

Given that:

Stress  level \sigma = 160 MPa

T = 0.5 Tm

\implies \dfrac{T}{Tm} = 0.5

G = 160 GPa

\implies \dfrac{\sigma}{G} = 10^{-3}

a)

The regulating creep mechanism is dislocation driven, as we can see from the deformation mechanism.

The engineer's recommendation would not be approved because increasing grain size results in a decrease in the grain-boundary count, preferring dislocation motion. The existence of grain borders is a hindrance to dislocation motion, as the dislocation principle explicitly states. To stop the motion, we'll need a substance with finer grains, which would result in more grain borders, or a material with higher pressure. In the case of Nabarro creep, which is diffusion-driven, an engineer's recommendation would be useful.

b)

If stress level reduced to \sigma = 1.6 MPa

\implies \dfrac{\sigma }{G} = 10^{-5}

Cable creep is now the controlling creep mode, which entails tension-driven atom diffusion along grain borders to elongate grain along the stress axis, a process known as grain-boundary diffusion. Cable creep is more common in fine-grained materials. As a result, the engineer's advice would succeed in this case. The affinity for cable creep is reduced when the grain size is increased.

c)

From the map of creep mechanism for \dfrac{\sigma}{G} = 10^{-3} \ and \ \dfrac{T}{Tm} = 0.5

We read strain rate (e) = 10^{-6}/sec

Therefore,

Strain (E) =  e * \Delta t

= 10^{-6} \times 10000 \times 3600

= 36

Therefore, \Delta L = E \times Li

= 36 * 10 cm

= 360 cm

Thus, the increase in length = 360 cm

7 0
4 years ago
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