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andreev551 [17]
3 years ago
7

A student earned grades of Upper AA​, Upper DD​, Upper AA​, Upper CC​, and Upper BB. Those courses had the corresponding numbers

of credit hours 44​, 22​, 22​, 33​, and 11. The grading system assigns quality points to letter grades as​ follows: Aequals=​4; Bequals=​3; Cequals=​2; Dequals=​1; Fequals=0. Compute the grade point average​ (GPA) as a weighted mean and round the result with two decimal places. If the​ Dean's list requires a GPA of 3.00 or​ greater, did this student make the​ Dean's list? The grade point average is nothing. ​(Round to two decimal places as​ needed.) Did this student make the​ Dean's list? A. Yes because at least two of the student grades are B or above B. No because the students GPA is not 4.0 C. NoNo because the student has at least one grade lessless than 3 D. NoNo because the​ student's GPA is lessless than 3.0
Mathematics
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer:

  • The grade point average is 2.92
  • The student didn't make the​ Dean's list because the​ student's GPA is less than 3.0

Step-by-step explanation:

  • I take the grades as A,D,A,C,B not AA​,DD​,AA​,CC​,BB.
  • I take numbers of credit hours as 4,2,2,3,1 not as 44​, 22​, 22​, 33​, and 11.

Since quality points to letter grades are A=​4; B=​3; C=​2; D=​1; F=0, weighted mean is the sum of the qulity points times corresponding credit hours divided by the total credit hours:

\frac{(4*4) + (1*2) + (4*2) + (2*3) + (3*1)}{12} ≈ 2.92

Since 2.92<3.0, the student is not in Dean's list.

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nydimaria [60]

Answer:

Step-by-step explanation:

As you can see, this is a quadratic equation and if you were to graph this you would see that it is a parabola that opens down because of the negative leading coefficient (-34). The maximum profit would be at the vertex, of the graph. Therefore, we need to find the value of "y" when "x" is the line of symmetry. We find this by  x=-b/(2a) where a = -34 and b = 1542:

x=-1542/(2)(-34)

x=-152/-68

x=152/68  

We put this value of "x" into the original formula to find out the value of "y":

y=-34x^2+1542x-10037

y=(-34)(1542/68)^2+1542(1542/68)-10037

y= -17483.5588235 + 34967.1176471 -10037

y=7446.5588236

Therefore, the maximum profit would be $7446.56.

Hope this helps!

PLS MARK BRAINLIEST THIS TOOK A LOT OF TIME

7 0
3 years ago
Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k
ch4aika [34]

Given

\vec v =  f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k

the curl of \vec v is

\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

7 0
3 years ago
What is the length of if ?<br><br> 8 in.<br> 8.75 in.<br> 10.25 in.<br> 14 in.
quester [9]

Answer:

Diagram attached

AJ = 8.75 in.  

Step-by-step explanation:

Since triangles HBA & HKJ are similar,    

BH/AH = KH/JH  

3 in /5.25 in = 8 in /JH  

JH = 14 in  

JA = JH - AH = JH - 5.25 in = 8.75 in


HJ = 14 in.

AJ = 14 in - 5.25 in  

AJ = 8.75 in.  

7 0
3 years ago
Using the equation F = ma, find the acceleration (a) of a 15 kg mass (m) that is acted on by 3 Newtons of Force (F). Group of an
Tcecarenko [31]

Answer:

Step-by-step explanation:

Yes

6 0
3 years ago
Read 2 more answers
How would I find x, I know it's an isosceles triangle but I so not know how to solve for it?????​
Wittaler [7]

Answer:

x=7 (if your teacher cares it could + or - 7)

Step-by-step explanation:

Okay, since it's a 90 degree triangle you can use the Pythagorean theorem

( a^2 + b^2 = c^2)

Since it's an isosceles triangle the other side is x because it's the same value.

x^2 + x^2= (7\sqrt{2} )^2

Add the left side

2x^2= 7^2 + \sqrt{2}^2 roots and square roots cancel each other out

So -> 2x^2= 49 x 2 =98

just solve for x.

x^2 = 98/2

x^2= 49

Square root both sides

x= 7

3 0
3 years ago
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