Question

As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10. If the cans are currently 12 cm tall, 6 cm in diameter, and have a volume of 339.12 cm3, how much more will the new cans hold? Use 3.14 for π and round your answer to the nearest hundredth. 112.25 cm3 373.03 cm3 451.37 cm3 790.49 cm3 Question 3(Multiple Choice Worth 1 points) (06.02 MC) The circumference of a redwood tree trunk is 16π ft, and it is 100 ft tall. What is the approximate volume of the redwood tree trunk? 2,560π ft3 640π ft3 25,600π ft3 6,400π ft3

Answer 1

Answer:

Question 1 ) Difference of Volume = 112.25 cm³

Question 2) Volume = 6400π feet³

Step-by-step explanation:

As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10. If the cans are currently 12 cm tall, 6 cm in diameter, and have a volume of 339.12 cm3, how much more will the new cans hold? Use 3.14 for π and round your answer to the nearest hundredth.

Diameter = 6 cm

Radius = 3 cm

Height = 12 cm

If we increase the dimension by 1.10, new dimesnions are:

Radius = 3 · 1.1 = 3.3 cm

Height = 12 · 1.1 = 13.2 cm

Volume = (Area)(Height) = (πr²)(Height)

Volume = (π)(3.3²)(13.2)

Volume = 451.37 cm³

Difference of Volume = 451.37 cm³ - 339.12 cm³

Difference of Volume = 112.25 cm³

The circumference of a redwood tree trunk is 16π ft, and it is 100 ft tall. What is the approximate volume of the redwood tree trunk?

Circumference = 2πr = 16π = 2π(8) feet

Radius = 8 feet

Volume = Volume = (Area)(Height) = (πr²)(Height)

Volume = (π)((8²)(100)

Volume = 6400π feet³