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never [62]
3 years ago
10

What is the degree of the polynomial below?2х^2 + 3x +1​

Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

the degree for the polynomial is 2

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Twice the difference of a number and 9 equals 5.
emmasim [6.3K]

Answer:

7

Step-by-step explanation:

if the number is x then you know 2x-9=5

2x=14

x=7

so the number is 7

8 0
3 years ago
Which of the following could be the lenght of the sides of a 30 -60 -90 degree triangle
cupoosta [38]
There’s no picture so I’ll give my own answers.
The long side needs to be x radical 3, the short leg is just x, and the hypotenuse is 2x. So one example could be 5 radical 3, 5, and 5 times 2
3 0
3 years ago
Read 2 more answers
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
with the square root of negative 1 in the numerator (the top) and eight in the demominator (on bottom) what is the answer
AleksAgata [21]
-1^2/8 = 1/8 is the answer
6 0
3 years ago
The area of a rectangular lawn is 255 metre square if its length is 15 M find its perimeter​
geniusboy [140]

Answer:

Step-by-step explanation:

width is 255/15=17

perimeter = 17*2+15*2=64

EZ

7 0
2 years ago
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