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Maurinko [17]
2 years ago
13

Please answer I am begging !!!

Mathematics
2 answers:
user100 [1]2 years ago
4 0

912 +e = 1201

Subtract 912 from each side:

e = 1201 - 912

e = 289



kati45 [8]2 years ago
3 0

The answer is e=289. You just minus 1201 by 912 to get 289.


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2 years ago
What must be added to both sides in 4x² + 24x + 8 = 32 in order to complete the square?
Sergeu [11.5K]

Answer:

16

Step-by-step explanation:

To solve a quadratic equation by using the completing the square method, the coefficient of the square term i.e x² must be one (1).

Therefore, we would have to first make the coefficient of x² to be equal to 1.

4x² + 24x + 8 = 32

We would simplify the equation;

4x² + 24x = 32 - 8

4x² + 24x = 24

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x² + 8x = 24

The value to be added = (8/2)² = 4² = 16

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x² + 4x + 4x + 16 = 24

x(x + 4) + 4(x + 4) = 24

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Taking the square root of both sides;

x + 4 = ± 4.9

x = -4 ± 4.9

x = -4 + 4.9 = 0.9

or

x = -4 - 4.9 = - 8.9

<em>Therefore, 16 must be added to solve the quadratic equation by completing the square method. </em>

6 0
3 years ago
How much cardboard needed to construct a rectangular prism measuring 15 inches by 13 inches by 7 inches
aleksandrvk [35]
1,365

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2 years ago
the length of a rectangle is 2 in more than it's w i d t h the area of a rectangle is equal to 1 inch less than three times a pe
Marizza181 [45]
If we let x and y represent length and width, respectively, then we can write equations according to the problem statement.
.. x = y +2
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This can be solved a variety of ways. I find a graphing calculator provides an easy solution: (x, y) = (13, 11).

The length of the rectangle is 13 inches.
The width of the rectangle is 11 inches.

______
Just so you're aware, the problem statement is nonsensical. You cannot compare perimeter (inches) to area (square inches). You can compare their numerical values, but the units are different, so there is no direct comparison.

6 0
3 years ago
Multiply.<br> (d+7)(d-7)<br> Simplify your answer.
romanna [79]

Answer:

\huge\boxed{(d+7)(d-7)=d^2-49}

Step-by-step explanation:

\bold{METHOD\ 1:}\\\\(d+7)(d-7)\qquad|\text{use}\ (a+b)(a-b)=a^2-b^2\\\\=d^2-7^2=d^2-49\\\\\bold{METHOD\ 2:}\\\\(d+7)(d-7)\qquad|\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(d)(d)+(d)(-7)+(7)(d)+(7)(-7)\\\\=d^2-7d+7d-49\qquad|\text{combine like terms}\\\\=d^2+(-7d+7d)-49\\\\=d^2-49

7 0
3 years ago
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