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USPshnik [31]
3 years ago
10

Find the average rate of change for the given function from x = -3 to x = 1.

Mathematics
1 answer:
Alika [10]3 years ago
3 0
Average rate of change from x = -3 to x = 1 is (f(1) - f(-3))/(1 - (-3)) = (5 - (-3))/(1 + 3) = (5 + 3)/4 = 8/4 = 2
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Which additional fact proves that ΔRST and ΔWXY are congruent if ∠T ≅ ∠Y and RT ≅ WY?
sergejj [24]

Answer:

Hence, option A is correct.

Step-by-step explanation:

We are asked to find the fact such that ΔRST and ΔWXY are congruent.

Since, we are given: ∠T ≅ ∠Y  and  RT ≅ WY.

we are given the following assumptions:

∠W = x + 5  

∠X = 3x - 9


∠Y = 2x + 4

as we are given one angle congruent and one side congruent so in order to prove two triangles are congruent we just need to show that one more pair of angles are congruent.

so from the two triangle we could have that ∠W≅∠R

and ∠X≅∠S

Now we will go by options:

A)

if ∠S=2x+20 then as ∠X≅∠S.

3x-9=2x+20

x=29

∠S=∠W=78°.

B)

if ∠R = 2x + 20 then as  ∠W≅∠R

⇒  x+5=2x+20

⇒ x= -15 which is not possible as it will make measure of angle W negative (x+5= -15+5= -10)

C)

if ∠S=2x^2+5 then as  ∠X≅∠S.

⇒ 3x-9=2x^2+5

⇒ 2x^2-3x+14=0

on solving this quadratic equation we will get complex zeros.

Hence, option (C) is not correct.

D)

if ∠R =  2x

^2

+ 5 then as ∠W≅∠R.

⇒ x+5=

2x

^2

+ 5

⇒ 2x^2-x=0

⇒ x(2x-1)=0

either x=0 or x=1/2 which is not  possible.

because by putting this x value in all the angles we see that sum of all the angles of a triangle is not equal  to 180°

Hence, option D is not possible.

Hence, option A is correct.



4 0
4 years ago
When completing the square on the equation c2 + 110 = 12, the resulting solution is:<br> It
Delvig [45]

Answer:

c=1 and c=-12

Step-by-step explanation:

The correct equation is:

c^2+11c=12

To solve by completing the square method.

Solution:

We have:

c^2+11c=12

In order to solve by completing the square method we will carry out the following operations to the given equation to get a perfect square binomial.

We can write as:

c^2+2.\frac{11}{2}c=12  

c^2+2.\frac{11}{2}c+(\frac{11}{2})^2-(\frac{11}{2})^2=12

(c+\frac{11}{2})^2-(\frac{11}{2})^2=12  [As  c^2+2.\frac{11}{2}c+(\frac{11}{2})^2=(c+\frac{11}{2})^2]

Adding both sides by (\frac{11}{2})^2

(c+\frac{11}{2})^2-(\frac{11}{2})^2+(\frac{11}{2})^2=12+(\frac{11}{2})^2

(c+\frac{11}{2})^2=12+\frac{121}{4}  

Taking LCD to add fraction.

(c+\frac{11}{2})^2=\frac{48}{4}+\frac{121}{4}

(c+\frac{11}{2})^2=\frac{169}{4}

Taking square root both sides.

\sqrt{(c+\frac{11}{2})^2}=\sqrt{\frac{169}{4}}

c+\frac{11}{2}=\pm\frac{13}{2}

Subtracting both sides by \frac{11}{2} :

c+\frac{11}{2}-\frac{11}{2}=\pm\frac{13}{2}-\frac{11}{2}

c=\pm\frac{13}{2}-\frac{11}{2}

So, we have:

c=\frac{13}{2}-\frac{11}{2} and c=-\frac{13}{2}-\frac{11}{2}

c=\frac{2}{2} and c=\frac{-24}{2}

c=1 and c=-12  (Answer)

6 0
4 years ago
A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What p
zubka84 [21]
I think 80%

I also got stuck on it and searched it up I think its 80% but if I'm wrong I'm sorry 
7 0
3 years ago
Read 2 more answers
What's the estimate of 608×8 ​
rusak2 [61]

Answer:

3,200

Step-by-step explanation:

you would have to multiply then estimate wich round it down an dyou get 3,200

3 0
3 years ago
Ten is 5% of what number?
Karo-lina-s [1.5K]

Answer:

200

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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