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3 years ago

Find the surface area of this composite solid.

Mathematics

1 answer:

Nataly_w [17]3 years ago

7 0

Answer: C

Step-by-step explanation:

The surface area of a pyramid = A + 1/2ps

Where A = area of the base

P = perimeter of base

S = slant height.

A = 4 × 4 = 16 m^2

P = 4L = 4 × 4 = 16 m

S = 3m

Surface area = 16 + 1/2 × 16 × 3

Surface area = 16 + 24

Pyramid surface area = 40 m^2

The surface area of the cuboid = LB + 2LH + 2BH

Where

B = width

H = height

L = length

Substitute all the parameters into the formula

Surface area = 4×4 + 2(4×5) + 2(4×5)

Surface area = 16 + 40 + 40

Surface area = 96 m^2

To Find the surface area of this composite solid, you will add the pyramid surface area to the cuboid surface area. That is

Total surface area = 40 + 96 = 136m^2

Therefore, the surface area of this composite solid is 136 cubic meters

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3.14=7x-2y

eimsori [14]

3.14=7x-2y

move 7x to the other side

sign changes from +7x to -7x

3.14-7x=7x-7x-2y

3.14-7x=-2y

Divide both sides by -2

3.14/-2-7x/-2=-2y/-2

3.14/-2=-1.57

-7x/-2=7x/2

Answer:

y=-1.57+7x/2

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3 years ago

The 10th term of an arithmetic proression is 68 and the common difference is 7 find the first term of the sequence

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Answer:

Step-by-step explanation:

first term + (10-1)7=68

first term= 68- 63=5

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2 years ago

What transformation takes the graph of f(x)=2x+3 to the graph of g(x)=2x+4 ?

Zolol [24]

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And the transformed function is g(x) = 2x+4.

We can see that if we add 1 into function f(x), we get

f(x) +1 or 2x+3+1 = 2x+4.

<h2>So, 1 is being added in original function f(x) and we get g function g(x) = 2x+4.</h2>

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2 years ago

Read 2 more answers

A student wants to determine the coefficients of static friction and kinetic friction between a box and a plank. She places the

Arturiano [62]

Answer:

the coefficients of static friction is 0.577

the coefficients of fkinetic friction is 0.54

Step-by-step explanation:

given information

θ = 30°

S = 2.5 m

t = 4 s

- Static friction

F - F(friction) = 0

W sin θ = μs W cos θ

μs = sin θ/ cosθ

= tan θ

= tan 30°

= 0.577

- kinetic friction

S = $v_{0} t$ + $\frac{1}{2} at^{2}$

$v_{0} t$ = 0

S = $\frac{1}{2} at^{2}$

a = $\frac{2S}{T^{2} }$ = $\frac{2 x 2.5}{4^{2} }$

= 0.3 $m/s^{2}$

F - F(friction) = m a

W sin θ - μ W cos θ = m a

mg sin θ - μk mg cos θ = m a

g sin θ - μk g cos θ = a

μk = g sin θ - a / g cos θ

= 9.8 sin 30° - 0.3 / 9.8 cos 30°

= 0.54

7 0

3 years ago

How do you solve this problem? population proportion is to be estimated from a sample of 400 with a sample proportion of 0.1. Ap

Ivan

Answer:

(0.0706, 0.1294)

Step-by-step explanation:

Confidence interval of a proportion is:

CI = p ± CV × SE

where p is the proportion,

CV is the critical value (z score or t score),

and SE is the standard error.

The sample is large enough to estimate as normal. For 95% confidence level, CV = z = 1.96.

Standard error for a proportion is:

SE = √(pq/n)

SE = √(0.1 × 0.9 / 400)

SE = 0.015

The confidence interval is:

CI = 0.1 ± (1.96)(0.015)

CI = (0.0706, 0.1294)

Round as needed.

6 0

2 years ago