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-BARSIC- [3]
2 years ago
14

The p-value for a one-sided test of the population proportion is 0.0513. Which of

Mathematics
1 answer:
uysha [10]2 years ago
3 0

Using the equation of the test statistic, it is found that with an increased sample size, the test statistic would decrease and the p-value would increase.

<h3>How to find the p-value of a test?</h3>

It depends on the test statistic z, as follows.

  • For a left-tailed test, it is the area under the normal curve to the left of z, which is the <u>p-value of z</u>.
  • For a right-tailed test, it is the area under the normal curve to the right of z, which is <u>1 subtracted by the p-value of z</u>.
  • For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is <u>2 multiplied by 1 subtracted by the p-value of z</u>.

In all cases, a higher test statistic leads to a lower p-value, and vice-versa.

<h3>What is the equation for the test statistic?</h3>

The equation is given by:

t = \frac{\overline{X} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{X} is the sample mean.
  • \mu is the tested value.
  • s is the standard deviation.
  • n is the sample size.

From this, it is taken that if the sample size was increased with all other parameters remaining the same, the test statistic would decrease,  and the p-value would increase.

You can learn more about p-values at brainly.com/question/26454209

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The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5
vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score,\bar x=3.5

Score(x)   frequency   C.F

1                  1                 1

2                  3                4

3                  f                 15(4+f=4+11)

4                  13               28

5                   4               32

\sum f_i=1+3+f+13+4=21+f

\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f

(\bar x)=\frac{\sum f_ix_i}{\sum f_i}

Using the formula

3.5=\frac{79+3f}{21+f}

73.5+3.5f=79+3f

3.5f-3f=79-73.5

0.5f=5.5

f=\frac{5.5}{0.5}=11

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}

Median=\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4

7 0
3 years ago
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