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posledela
2 years ago
13

PLEASE HURRY ASAP I NEED IT ASAPP PLEASE SHOW YOUR WORKKK I WILL MAKE YOU BRAINLIEST

Mathematics
1 answer:
Arturiano [62]2 years ago
6 0

Answer:

  BD = √97 cm ≈ 9.849 cm

Step-by-step explanation:

Diagonal BD of rectangle ABCD is the hypotenuse of right triangle ABD. Opposite sides of the rectangle are the same length, so we have ...

  AB = 4 cm

  AD = 9 cm

The sides are related to the diagonals by the Pythagorean theorem.

<h3>Pythagorean theorem</h3>

The Pythagorean theorem tells you the relation between sides and hypotenuse of a right triangle:

  AB² +AD² = BD²

  4² +9² = BD² = 16 +81 . . . . . evaluating the squares

  BD = √97 . . . . . take the square root

The length of BD is √97 cm, about 9.849 cm.

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kotykmax [81]

Answer:

if you have to add it is 17  

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Step-by-step explanation:

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3 years ago
Help please can someone break these problems down for me so I can show my son thanks in advance!:)
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For the second question (5/6)/(4) is the same as (5/6)*(1/4) so just multiply across and you get (5/24)
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What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
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