The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
To learn more on quadratic functions: brainly.com/question/5975436
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I can’t see can you put it closer
Answer:
105 ft.
Step-by-step explanation:
5 x 12 = 60
So 5 feet is 60 inches.
60 + 3 = 63
That makes the ridge 63 inches long.
When the lion went up the ridge, it traveled 63 inches.
When the lion went back down the ridge, it traveled another 63 inches, totaling 126 inches.
The lion did this 10 times.
126 x 10 = 1260
Divide 1260 by 12 to find the measurement in feet.
1260 ÷ 12 = 105