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1 year ago

Find the measure of line segment DF. A) 12 B) 13 C) 14 D) 15

Mathematics

1 answer:

brilliants [131]1 year ago

4 0

As per the Intersecting Chords theorem, if two chords cross in a circle, the products of the chord segments' measures are equal. The measure of the line segment is DF is 14 units.

<h3>What is Intersecting Chords theorem?</h3>

If two chords cross in a circle, the products of the chord segments' measures are equal.

As per the Intersecting Chords theorem, the product of DF and FB will be equal to the product of CF and FA, therefore,

DF×FB = CF×FA

(x+8) × 8 = 16 × 7

(x+8) = (16×7)/8

(x+8) = 14

Hence, the measure of the line segment is DF is 14 units.

Learn more about Intersecting Chords theorem:

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Which of the following expressions are equivalent to -5/-7×-11/-6

USPshnik [31]

Answer:

Step-by-step explanation:

-5/-7×-11/-6

= (-5 * -11) / (-7*-6)

= 55 / 42.

A. = - (6/-11) = 6/11

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B. - (-11/7) = 11/7

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2 years ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$