Angle QPS is an inscribed angle. Arc QS is the intercepted arc of that angle. The rule is that the intercepted arc is twice its angle measure. P measures 20 degrees, so arc QS measures 40 degrees. It just so happens that angle QTS is ALSO an inscribed angle intercepting arc QS. So angle QTS measures the same as angle P, 20 degrees. That's a. For b., we already stated the rule and figured out that minor arc QS is 40 degrees. For c., major arc QTS is 360 (the measure around the outside of a circle...EVERY circle in the world) minus the minor arc of 40. So major arc QTS measures 360 - 40 which is 320 degrees. There you go!
Answer:
Step-by-step explanation:
The distance is given by the expression![d=\sqrt{(\Delta x)^2+(\Delta y)^2}= \sqrt{[(-2)-(-7)]^2+[(-5)-(1)]^2} = \sqrt{(-2+7)^2+(-5-1)^2}=\sqrt{(5)^2+(-6)^2}=\sqrt{(25+36)}=\sqrt {61}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28%5CDelta%20x%29%5E2%2B%28%5CDelta%20y%29%5E2%7D%3D%20%5Csqrt%7B%5B%28-2%29-%28-7%29%5D%5E2%2B%5B%28-5%29-%281%29%5D%5E2%7D%20%3D%20%5Csqrt%7B%28-2%2B7%29%5E2%2B%28-5-1%29%5E2%7D%3D%5Csqrt%7B%285%29%5E2%2B%28-6%29%5E2%7D%3D%5Csqrt%7B%2825%2B36%29%7D%3D%5Csqrt%20%7B61%7D)
The answer for this is the rules is x n y
Answer:
A
Step-by-step explanation:
1 ton is equal to 2,000lbs. So if you multiply 4 and 2,000 you should end up with 8,000lbs, not 6,000lbs.
Answer:
The first step is to replace the y in y-x=15 with 7x (we can do this because the first equation tells us that they're equal)
solve and get
(2.5,17.5)
or x= 2.5 y=17.5
Step-by-step explanation:
The first step is to recognize that y=7x which means that we can just replace the y in the second equation with 7x
7x-x=15
6x=15
x=2.5
Then we can solve for y
y=7(2.5)
y=17.5
