I have a feeling I've seen this question before
anyway
A=number of hours that plan A is
B=number of hours that plan B is
so
on wednesday, 7hr
5A and 6B so
5A+6B=7
on thursday, 3 hours
3 of A and 2 of B
3A+2B=3
so we gots
5A+6B=7
3A+2B=3
elimination
eliminate B's
multiply 2nd equation by -3 and add to 1st equation
5A+6B=7
<u>-9A-6B=-9 +</u>
-4A+0B=-2
-4A=-2
divide both sides by -4
A=1/2
A=0.5
sub back
3A+2B=3
3(0.5)+2B=3
1.5+2B=3
minus 1.5 both sides
2B=1.5
divide by 2 both sides
B=0.75
plan A lasts 1/2 hour or 0.5 hour or 30 mins
plan B lasts 3/4 hour or 0.75 hour or 45 mins
I do i posted a lot of math do the one that i posted a long time ago
Answer:
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Step-by-step explanation:
Answer:
It is 91% more likely that the tree was atmost 500 yards from the river.
<h3>Step-by-step explanation:</h3>
We are given with distance and height of 100 young trees near a river.
From that table, in total there are 55 trees which grow more than 3 ft during the year.
And among those 55 trees, 50 trees are atmost 50 yards from river.
Hence it is ≈91% more likely that the tree was atmost 50 yards from the river.
