explain how estimated the quotient helps you place the first digit in the quotient of a division problems

Mohamed decided to track the number of leaves on the tree in his backyard each year. the first year, there were 500500500 leaves

VARVARA [1.3K]

Mohamed decided to track the number of leaves on the tree in his backyard each year. the first year, there were 500 leaves. each year thereafter, the number of leaves was 40% more than the year before. let f(n) be the number of leaves on the tree in Mohamed's backyard in the n^th year since he started tracking it. f is a sequence. what kind of sequence is it?

Number of leaves on the tree in first year = 500

The number of leaves was 40% more than the year before.

So rate of increase is 40/100 = 0.4

We use exponential growth formula,

f(n) = a(1+r)^n

Where a is the initial number, r is the rate of growth, n is the number of years

We know a= 500, r= 0.4

f(n) = 500(1+0.4)^n

f(n) = 500(1.4)^n

Plug in n=1,2,3...

f(1) = 500

f(2) = 500 * 1.4^1

f(3) = 500 * 1.4^2 and so on

From this we can see that the common ratio is 1.4

Hence it is a Geometric sequence.

8 0

3 years ago

Read 2 more answers

which of the following polynomials has a graph with odd symmetry? a. 7x^4+13x^3-11 b. 5x^7+4x^6+3x^5+x c.13x^5 -1/2x^3+7x+3 d. 8

agasfer [191]

Answer: 45x3x345!3

Step-by-step explanation:

you multiply all numbers then you divide by all the numbers there and there’s your answer

6 0

2 years ago

Read 2 more answers

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

2 years ago

You have a credit card with a balance of 1187.92 and the interest is 12.25% apr. a late fee of 30.00 is charged for payments aft

Travka [436]

We start with
$1,187.92
With the interest and the late fee charge
$1,187.92 (1 + 0.1225/12) + 30 = $1,230.05
With the interest minus the payment of $125
$1,230.05 (1 + 0.1225/12) - $125 = $1,117.60

The new principal after the latest payment is $1,117.60.

7 0

2 years ago

Read 2 more answers

29. Determine the value of x.<br> abc<br> X + 42°<br> 147°<br> 2x

suter [353]

Answer:

x=35

Step-by-step explanation:

180-147=33 (angles in a straight line)

33+3x+42=180 (angles in a triangle)

3x+42=147

147-42=105

105/3=35

5 0

1 year ago