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d1i1m1o1n [39]
3 years ago
6

Please help asap 22 pts

Mathematics
2 answers:
Lisa [10]3 years ago
8 0

D: (-1, -1) im pretty sure at least.

Flauer [41]3 years ago
4 0

Hello!  The answer that you are looking for is D: (-1, -1).  Hope this helps!

P.S.

Could you mark me brainliest?  It will really help me.  Thanks!

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X/4 -3 = 1/3 + 2x solve for x
ivann1987 [24]

Answer:

Step-by-step explanation:

\frac{x}{4} - 3 = \frac{1}{3} + 2x ...... <em>(1)</em>

(1) × 12 :

3x - 36 = 4 + 24x

21x = - 40

x = - \frac{40}{21} = -1\frac{19}{21}

4 0
3 years ago
Please help this is due today at 6
seropon [69]

Answer:

The answer i got was 7 and 7/10

Step-by-step explanation:

6 4/10+7/10+6/10=7 7/10

7 0
3 years ago
What is the answer of 9.34-3.029=
Shalnov [3]
In case the user wants to see workings. These problems can easily be solved on a calculator, but can we work them out in our heads? ;)

9.34-3.029

=9.340-3.029

=9.340-3.000-0.029

=6.340-0.029

=6.311
8 0
3 years ago
II. The following figure shows an infinite zigzag path with each zag
nataly862011 [7]

The length of the infinite zigzag path is 1

<h3>How to determine the length</h3>

Note that the infinite zigzag path is embedded in an isosceles triangle

Using angle π/4, we have that

Tan π/4 = opposite/ adjacent

tan \frac{3. 412}{4}  = \frac{x}{1}

tan 0. 7855 = x

x = 0. 014

To find the longer part 'y',  use the Pythagorean theorem

y^{2} = (0.014)^2 + (1)^2

y^2 = 1.879 * 10^-4 + 1
y^2 = 1. 00

y = \sqrt{1. 000}

y = 1. 000

The length of the infinite zigzag path is the same as the length of the longer part of the triangle which equals 1.

Thus, the length of the infinite zigzag path is 1

Learn more about the Pythagorean theorem here:

https://brainly.in/question/48490459

#SPJ1

8 0
2 years ago
Tìm x €N: a) 24:(2x-4)+14=26
professor190 [17]

Answer:

2x-4+14=26    add -4+14 this will give you +10

2x+10=26       subtract 10 on both side this will give you 16

2x=16        divide by 2 on both side this will give you 8

x=8

Step-by-step explanation:

8 0
3 years ago
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