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marin [14]
2 years ago
14

Match the graph with the correct equation. Please help!

Mathematics
1 answer:
galina1969 [7]2 years ago
6 0

Answer:

y = -x -2

Step-by-step explanation:

The graph has a slope of -1 and a y-intercept of -2.

The equation is therefore

y = -x -2

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−7m+4&lt;−45 <br><br> its an one-step problem help me please
aleksandr82 [10.1K]

Answer:

x > 7

Step-by-step explanation:

- 7m + 4 < - 45 ( subtract 4 from both sides )

- 7m < - 49

Divide both sides by - 7 , reversing the symbol as a result of dividing by a negative quantity.

m > 7

7 0
2 years ago
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What is the third quartile of this data set 20,21,24,25,28,29,35,36,37,43,44
SashulF [63]

Answer:

37

Step-by-step explanation:

The data set is in ascending order, thus the median is the middle value of the data set.

median = 29

The third quartile is the middle value of the data to the right of the median

Q_{3} = 37

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3 years ago
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Which is NOT an undefined term in geometry
Anna71 [15]
There are three words in geometry<span> that are </span>not<span> formally defined. These three </span>undefined terms<span> are point, line and plane.</span>
3 0
3 years ago
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In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
Write one hundred and fourteen thousandths as a decimal number.
LiRa [457]

100.014. I think this is it

6 0
3 years ago
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