The test statistic z will be equal to -0.946 and it shows that there is no significant difference in the proportion of rehires between full time and part time.
Given sample sizes of 833 and 386 and result of samples 434 and 189.

Proportion of full time=434/833=0.52
Proportion of part time=189/386=0.49.
Difference in proportion =0.52-0.49
TTF- i∈ rho=0
TTF+i∈ rho≠0.
Mean of difference=0.03
Z=(X-μ)/σ
σ=
=0.0317
σ=0.0317
z=(0-0.03)/0.0317
=-0.03/0.0317
=-0.317
p value will be =0.1736.
Because p value is greater than 0.01 so we will accept the null hypothesis which shows that there is no significant difference in the proportions.
Hence there is no significant difference in the proportion of rehires between full time and part time.
Learn more about z test at brainly.com/question/14453510
#SPJ4
Answer:

Step-by-step explanation:
8x+9=0
8x=-9

or

,



, 
Answer:
answer would be the first choice.
Step-by-step explanation:
you would need to factor out x from the expression, then factor out -3 from the expression, factor the expression using a^2-B^2=(a-b)(a+b), afterwards you factor out the 4 from the expression, and then the 3x. Next you would factor out 2x+1, reduce the expression with x-5, reduce the numbers with the greatest common divisor 2, you then reduce the expression with x-3, multiply the fractions, distribute 2 through the parenthesis, distribute the 3x through the parenthesis, and that should be all.