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2 years ago

9 3/5 times 3 1/2 equals

Mathematics

1 answer:

Oduvanchick [21]2 years ago

3 0

Answer:33.6

Step-by-step explanation:

first change the mixed numbers into improper fractions

so: 9×5±3 =48

and 3×2+1=7

<h3>so $\frac{48}{5} times \frac{7}{2}$ </h3><h3>48 ×7=336 and 5×2=10</h3><h3>so $\frac{336}{10} =33.6$ </h3><h3>hope this helps!!!!!</h3>

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The equation of line WX is y = −2x − 5. Write an equation of a line perpendicular to line WX in slope-intercept form that contai

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Answer:

third option

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x - 5 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-2}$ = $\frac{1}{2}$ , then

y = $\frac{1}{2}$ x + c ← is the partial equation

To find c substitute (- 1, 1) into the partial equation

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2 years ago

Higher order thinking. Rectangular prism can have a volume of 12 cubic units

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Answer:

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Step-by-step explanation:

Volume is the product of the three dimensions: length, width, and height.

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2 years ago

In a group of 700 people only 5% of them have red hair how many people hade red hair

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Step-by-step explanation:

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2 years ago

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How to solve x=6y-11 and 3x-2y=-1 by substitution

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Substitute x into the second equation:
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2 years ago

Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-

Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

$\sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

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