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eduard
3 years ago
9

Hey guys! 20 points! Please help! A model rocket is launched from a roof into a large field. The path of the rocket can be model

ed by the equation y = -0.04^2+ 5.8x + 4.9, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?
Mathematics
1 answer:
Georgia [21]3 years ago
6 0

Answer:

145.84 meters

Step-by-step explanation:

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Let's focus on 0.7*0.8 for now. 

Start by drawing a large square. Cut this figure into 10 rows and 10 columns. So this means you'll have 10*10 = 100 little squares. 

Now highlight the first 7 rows. Shade in all 70 squares (7*10 = 70)
Starting on the left side, highlight the first 8 columns. You'll shade in 80 squares (8*10 = 80)

Use different colors for your highlighting or somehow indicate different shading styles. This way you can see the overlapping region. The overlapping region consists of 56 squares (7 rows, 8 columns ---> 7*8 = 56 little squares)

Each little square represents 0.01, so having 56 of them means we have 0.56

This shows that 0.7*0.8 = 0.56

-----------------------------------------------------------

How is this different if we had 1.7*0.8? Well we can break 1.7 into 1+0.7 to have

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1.7*0.8 = (1)*0.8+(0.7)*0.8
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The portion (0.7*0.8) was done earlier. That result was 0.56. So we just need to compute (1*0.8), which is simply 0.8; recall that 1 times any number is that number itself.

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