The process of condensation it releases energy up into the atmosphere where the clouds form.
Answer: (1). There are 0.0165 moles of gaseous arsine (AsH3) occupy 0.372 L at STP.
(2). The density of gaseous arsine is 3.45 g/L.
Explanation:
1). At STP the pressure is 1 atm and temperature is 273.15 K. So, using the ideal gas equation number of moles are calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
2). As number of moles are also equal to mass of a substance divided by its molar mass.
So, number of moles of Arsine (molar mass = 77.95 g/mol) is as follows.
Density is the mass of substance divided by its volume. Hence, density of arsine is calculated as follows.
Thus, we can conclude that 0.0165 moles of gaseous arsine (AsH3) occupy 0.372 L at STP and the density of gaseous arsine is 3.45 g/L.
Answer:
20
Explanation:
The acceleration in this problem is 20
Acceleration is defined as the rate of change of velocity with time. When a force is exerted on a body and the net force is greater than zero, it begins to accelerate.
- A golf ball often accelerate from rest when being hit.
- Its initial velocity in this instance is usually zero.
- As it is hit, the acceleration increases to a point where it begins to tend towards zero is momentum decreases.
- From the given problem, the mass of the ball is 0.2kg and the acceleration is 20m/s²
Answer: The initial temperature was 263 K
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 0.939 atm
= final pressure of gas = 1.00 atm
= initial volume of gas = 9.40 L
= final volume of gas = 10.0 L
= initial temperature of gas = ?
= final temperature of gas =
Now put all the given values in the above equation, we get:
Thus the initial temperature was 263 K