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shutvik [7]
3 years ago
5

Can someone help me please

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

181.25 square feet

1/6 quart water

1/18 cup milk

1/3 beef bouillon cube, and 2/3 a large carrot

Step-by-step explanation:

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213=22: Z=14 Select True or False for each equation as is state<br> O True<br> O False<br> 5x=25
nignag [31]
Truest sense that the world of war in my opinion was gon in my own name in
3 0
2 years ago
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
best answer will be awarded the brainliest and 5 stars choose the best estimate for 278 divided by 59 select the correct answer
Alex Ar [27]
278 divided by 59 is 4.712, which can be rounded to 5
the answer is d. 5
5 0
3 years ago
Read 2 more answers
What would the answer be
ArbitrLikvidat [17]

Answer:

12x^4-35x^3+45x^2-13x-15

Step-by-step explanation:

some issues with the signa

3 0
3 years ago
-x+ 2y = 10<br> -3x+By = 11
adoni [48]

Answer:

change the equation into one variable.

2 y equals 10 + x

y equals 5 + x by 2

now put that into the second equation

-3x + b parentheses 5 + x / 2 equals 11

-3x+b(5+ x/2)

-3x + b5 + bx/2 = 11

8 0
3 years ago
Read 2 more answers
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