All categories

3 years ago

Help please ( ˶ ❛ ꁞ ❛ ˶ )

Mathematics

2 answers:

pentagon [3]3 years ago

6 0

Answer:

179.25 cm squared

Step-by-step explanation:

14*10=140

3.14(5)^2=78.5/2=39.25

140+39.25=179.25

VashaNatasha [74]3 years ago

4 0

179.25in squared is the answer (press thanks plz)

You might be interested in

How do you turn f(x) = 3x 2– 40x + 180 into a graph?

Nuetrik [128]

Answer:

Intersept is (4.55,0)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

2 x 10 + 4 x 1 + (7 x 1/10) + (4 x 1/100) + (5 x 1/1000) in standard form

Verizon [17]

Answer:

4949/200=

Step-by-step explanation:

5 0

3 years ago

The Adventures of Huckleberry Finn, written by Mark Twain, has an ISBN of 978-014243717a, where a is the check number. What is t

Simora [160]

Answer: D. 9

Step-by-step explanation:

4 0

3 years ago

39,477 round to 1,000

user100 [1]

40,000 is your answer hope I could help

6 0

3 years ago

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

_______________

$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0

3 years ago

Help please ( ˶ ❛ ꁞ ❛ ˶ ) ​

Help please ( ˶ ❛ ꁞ ❛ ˶ )