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hoa [83]
3 years ago
12

What are the solution for the quadratic equation y=x^2+11x+24

Mathematics
1 answer:
Fed [463]3 years ago
7 0
<span>Simplifying x2 = 11x + -24 Reorder the terms: x2 = -24 + 11x Solving x2 = -24 + 11x Solving for variable 'x'. Reorder the terms: 24 + -11x + x2 = -24 + 11x + 24 + -11x Reorder the terms: 24 + -11x + x2 = -24 + 24 + 11x + -11x Combine like terms: -24 + 24 = 0 24 + -11x + x2 = 0 + 11x + -11x 24 + -11x + x2 = 11x + -11x Combine like terms: 11x + -11x = 0 24 + -11x + x2 = 0 Factor a trinomial. (3 + -1x)(8 + -1x) = 0 Subproblem 1Set the factor '(3 + -1x)' equal to zero and attempt to solve: Simplifying 3 + -1x = 0 Solving 3 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1x = 0 + -3 -1x = 0 + -3 Combine like terms: 0 + -3 = -3 -1x = -3 Divide each side by '-1'. x = 3 Simplifying x = 3 Subproblem 2Set the factor '(8 + -1x)' equal to zero and attempt to solve: Simplifying 8 + -1x = 0 Solving 8 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1x = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1x = 0 + -8 -1x = 0 + -8 Combine like terms: 0 + -8 = -8 -1x = -8 Divide each side by '-1'. x = 8 Simplifying x = 8Solutionx = {3, 8}</span>
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Can anyone help me solve these math problems?
Veseljchak [2.6K]

Answer:

  1. x = 2
  2. r = 48
  3. 3536 ft
  4. √10
  5. 10°

Step-by-step explanation:

1. The Pythagorean theorem applies, so the sum of the squares of the legs is equal to the square of the hypotenuse.

  x² + (x+3)² = (√29)²

  2x² +6x +9 = 29 . . . . . . eliminate parentheses, collect terms

  2x² +6x -20 = 0 . . . . . . subtract 29

  x² +3x -10 = 0  . . . . . . . . divide by 2

  (x +5)(x -2) = 0 . . . . . . . . factor

x = -5 or +2 . . . . . . . . . . . . values that make the factors zero (-5 is extraneous)

The value of x is 2.

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2. Even though the figure is drawn incorrectly the Pythagorean theorem still applies. (The second attachment shows the circle in the right place. The figure is not to scale.)

  14² + r² = (r+2)²

  196 + r² = r² +4r +4 . . . . eliminate parentheses

  192 = 4r . . . . . . . . . . . . . .subtract r²+4 from both sides

  48 = r . . . . . . . . . . . . . . . . divide by 4

The value of r is 48.

__

3. You will recognize that the triangle involving the distance above the ground, the distance along the ground, and the straight-line bullet path is an isosceles right triangle. So, the hypotenuse is √2 times the length of either leg. The path length of the bullet is ...

  (2500 ft)√2 ≈ 3536 ft

__

4. see below for the diagram

The length to the terminal point is found using the Pythagorean theorem:

  d = √(3² +(-1)²) = √10

The distance from the origin to the terminal point is √10 ≈ 3.16.

__

5. Angles "a" and "8a" total 90°, so we have ...

  a + 8a = 90°

  9a = 90° . . . . . . . . collect terms

  a = 10° . . . . . . . . . . divide by 9

The value of a is 10°.

8 0
3 years ago
Please help if you know this
nikdorinn [45]

Answer:

First degree

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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