Multiply 18hours by 60 seconds, the answer is 2880 seconds.
You should have drawn1 - x-axis and y-axis in light pencil.2 - graphed a down-facing parabola with the top of the frown on the y-axis at y = 2. It should be crossing the x-axis at ±√2. This should be in dark pencil or another color.3 - In dark pencil or a completely new color, draw a rectangle with one of the horizontal sides sitting on top of the x-axis and the other horizontal side touching the parabola at each of the top corners of the rectangle. The rectangle will have half of its base in the positive x-axis and the other half on the negative x-axis. It should be split right down the middle by the y-axis. So each half of the base we will say is "x" units long. So the whole base is 2x units long (the x units to the right of the y-axis, and the x units to the left of the y-axis) I so wish I could draw you this picture... In the vertical direction, both vertical edges are the same length and we will call that y. The area that we want to maximize has a width 2x long, and a height of y tall. So A = 2xy This is the equation we want to maximize (take derivative and set it = 0), we call it the "primary equation", but we need it in one variable. This is where the "secondary equation" comes in. We need to find a way to change the area formula to all x's or all y's. Since it is constrained to having its height limited by the parabola, we could use the fact that y=2 - x2 to make the area formula in only x's. Substitute in place of the "y", "2 - x2" into the area formula. A = 2xy = 2x(2 - x2) then simplify A = 4x - 2x3 NOW you are ready to take the deriv and set it = 0 dA/dx = 4 - 6x2 0 = 4 - 6x2 6x2 = 4 x2 = 4/6 or 2/3 So x = ±√(2/3) Width remember was 2x. So the width is 2[√(2/3)]Height is y which is 2 - x2 = 2 - 2/3 =4/3
Answer:
Option (A)
Step-by-step explanation:
By satisfying the equation of a function 'f' by each coordinates given in the options we can get the point which lies on the graph of f(x) = 
Option (A). (1, 10)
f(1) = 
10 = 10
True.
Therefore, point (1, 10) lies on the graph.
Option (B). (0, 10)
f(0) = 
10 = 2
Not true.
Therefore, point (0, 10) doesn't lie on the graph.
Option (C). (10, 1)
f(10) = 
1 = 19531250
Not true.
Therefore, point (10, 1) doesn't lie on the graph.
Option (D). (0, 0)
f(0) =
0 = 2
Not True.
Point (0, 0) doesn't lie on the graph.
Option (A) will be the answer.
Let's simplify step-by-step.<span><span><span><span>8.9x</span>−5</span>−<span>6.8x</span></span>+8</span><span>=<span><span><span><span><span><span>8.9x</span>+</span>−5</span>+</span>−<span>6.8x</span></span>+<span>8
</span></span></span>Combine Like Terms:<span>=<span><span><span><span>8.9x</span>+<span>−5</span></span>+<span>−<span>6.8x</span></span></span>+8</span></span><span>=<span><span>(<span><span>8.9x</span>+<span>−<span>6.8x</span></span></span>)</span>+<span>(<span><span>−5</span>+8</span>)</span></span></span><span>=<span><span>2.1x</span>+<span>3
The simplified answer is </span></span></span><span><span>2.1x</span>+<span>3</span></span>
Given,
Cylinder A has a volume of 6 cubic units
and height =3 units
The radius of cylinder A,
![\begin{gathered} r=\sqrt[]{\frac{V}{\pi h}} \\ =\sqrt[]{\frac{6}{3\pi}} \\ =0.8 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%3D%5Csqrt%5B%5D%7B%5Cfrac%7BV%7D%7B%5Cpi%20h%7D%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B%5Cfrac%7B6%7D%7B3%5Cpi%7D%7D%20%5C%5C%20%3D0.8%20%5Cend%7Bgathered%7D)
To find the volume of a cylinder B
Thus the volume of cylinder B is 6.03
