Help me pleasssseeeeeee

Mathematics

1 answer:

fgiga [73]3 years ago

3 0

Answer:

d. Distributive property

Step-by-step explanation:

The Distributive property of multiplication over addition is what allows you to multiply each of the terms in parentheses by the factor outside parentheses. It tells you ...

a(b +c) = ab + ac

It works both ways, also allowing you to remove a common factor to outside parentheses.

You might be interested in

YALL HELP plz give me a fraction problem that contains division and multiplication !!

Luba_88 [7]

Answer:

This one is a bit easy, so if you need a harder one, just let me know.

((32/48) x (4/6)) / (2/5)

Step-by-step explanation:

1) You can simplify both (32/48) and (4/6) to (2/3).

2) Multiply (2/3) by itself, giving (4/9).

3) Dividing by a fraction is equivalent to multiplying by its reciprocal, or opposite. In this example, the reciprocal of (2/5) is (5/2). Thus, (4/9) x (5/2) = (20/18).

4) Simplify your answer, to (10/9) or 1 and 1/9 (as a mixed fraction).

4 0

3 years ago

Find the difference. Express your answer in simplest form. 7r/s - 4r/s

Scrat [10]

$7 \frac{r}{s} \: - 4 \frac{r}{s} \\ taking \: common \: factor \: ( \frac{r}{s} ) \\ = \frac{r}{s} (7 - 4) \\ =3 \frac{r}{s}$

Hope it helps...

Regards;

Leukonov/Olegion.

7 0

3 years ago

Brainliest answer

Flura [38]

A geometric sequence is a sequence of numbers that follows a pattern where the next term is found by multiplying by a constant called the common ratio, q:

$a_n=a_{n-1}\cdot q=(a_{n-2}\cdot q)\cdot q=a_{n-2}\cdot q^2=...,\\ a_n=a_1\cdot q^{n-1}$ .

Given the functions $f(n)=11$ and $g(n)=\left(\dfrac{3}{4}\right)^{n-1}$ , you can consider $a_n=11\cdot \left(\dfrac{3}{4}\right)^{n-1}$ as n-th term of the geometric sequence with first term $a_1=11$ and common ratio $q=\dfrac{3}{4}$ .