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swat32
4 years ago
5

The proprietor of Midland Construction Company has to decide between two projects. He estimates that the first project will yiel

d a profit of $170,000 with a probability of 0.7 or a profit of $130,000 with a probability of 0.3; the second project will yield a profit of $230,000 with a probability of 0.7 or a profit of$80,000 with a probability of 0.3.
Find the expected profit for each project.

first project = ?
second project = ?
Mathematics
1 answer:
Colt1911 [192]4 years ago
7 0

Answer: Expected profit for first and second project are $158000 and $185000 respectively.

Step-by-step explanation:

Since we have given that

First project :

a profit of $170,000 with a probability of 0.7 or a profit of $130,000 with a probability of 0.3

0.7      $170000

0.3      $130000

So, Expected profit would be

E[x]=\sum xp(x)=0.7\times 170000+0.3\times 130000=\$158000

Second project:

a profit of $230,000 with a probability of 0.7 or a profit of$80,000 with a probability of 0.3.

0.7      $230000

0.3      $80000

So, Expected profit would be

E[x]=\sum xp(x)=0.7\times 230000+0.3\times 80000=\$185000

Hence, expected profit for first and second project are $158000 and $185000 respectively.

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4 years ago
Which is another way to check the sum of 104+34+228+877?
Alex787 [66]
The answer is digit sum method.

Digit sum method is method used to check the sum of sum numbers. If the sum of all of the digits of numbers is equal to the sum of all of the digits of the total sum, then the arithmetic process was correct.

We need to check the sum of <span>104+34+228+877:
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Let's first summarize the digits of individual numbers:
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3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \
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\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2

Step-by-step explanation:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} = \ ?

We can use Part I of the Fundamental Theorem of Calculus:

  • \displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

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We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

  • \displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

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We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

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Simplify the expression by distributing 2 and 2x inside their respective parentheses.

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This is the derivative of the given integral, and thus the solution to the problem.

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