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Rashid [163]
3 years ago
7

Database management systems are expected to handle binary relationships but not unary and ternary relationships.'

Computers and Technology
1 answer:
alekssr [168]3 years ago
6 0

Answer:

False          

Database management systems are expected to handle binary, unary and ternary relationships.

Explanation:

Unary Relationship: It is a recursive relationship which includes one entity in a relationship which means that there is a relationship between the instances of the same entity. Primary key and foreign key are both the same here. For example a Person is married to only one Person. In this example there is a one-to-one relationship between the same entity i.e. Person.

Binary Relationships: It is a relationship involving two different entities.   These two entities identified using two relations and another relation to show relationship between two entities and this relation holds primary keys of both entities and its own primary key is the combination of primary keys of the both relations of the two entities. For example Many Students can read a Book and many Books can be obtained by a Student.

Ternary Relationships: is a relationship involving three entities and can have three tables. For example a Supplier can supply a specific Part of many Mobiles. Or many Suppliers may supply several Parts of many Mobile models.

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Write a program which increments from 0 to 20 and display results in Decimal on the console 2-b) Modify above program to increme
SVEN [57.7K]

Answer:

<em>This program is written in C++</em>

<em>Comment are used to explain difficult lines</em>

<em>The first program that prints 0 to 20 (in decimal) starts here</em>

#include<iostream>

int main()

{

//Print From 0 to 20

for(int i = 0;i<21;i++)

{

 std::cout<<i<<'\n';

}

}

<em>The modified program to print 0 to 20 in hexadecimal starts here</em>

#include<iostream>

using namespace std;

int main()

{

//Declare variables to use in conversion;

int tempvar, i=1,remain;

//Declare a char array of length 50 to hold result

char result[50];

//Print 0

cout<<"0"<<endl;

// Iterate from 1 to 20

for(int digit = 1; digit<21; digit++)

{

//Start Conversion Process

//Initialize tempvar to digit (1 to 20)

tempvar = digit;

while(tempvar!=0)

{

//Divide tempvar by 16 and get remainder

remain = tempvar%16;

if(remain<10)

{

 result[i++]=remain + 48;

}

else

{

 result[i++] = remain + 55;

}

//Get new value of tempvar by dividing it by 16

tempvar/=16;

}

//Print result

for(int l=i-1;l>0;l--)

{

cout<<result[l];

}

i=1;

cout<<endl;  

}

return 0;

}

//The Program Ends Here

See Attachments for program 1 and 2; program 2 is the modified version of 1

Download cpp
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> cpp </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> cpp </span>
3 0
3 years ago
The K-Means algorithm terminates when:_______
gavmur [86]

Answer:

b. the cluster centers for the current iteration are identical to the cluster centers for the previous iteration.

Explanation:

K-mean algorithm is one of the mot widely used algorithm for partitioning into groups of k clusters. This is done by partitioning observations into clusters which are similar to each other. When using k-mean algorithm, each of the different clusters are represented by their centroid and each point are placed only in clusters in which the point is close to cluster centroid.

The K-Means algorithm terminates when the cluster centers for the current iteration are identical to the cluster centers for the previous iteration.

7 0
4 years ago
Which tools can be used to scale an object? Check all that apply.
meriva

Answer:

format picture pane

corner sizing handles

Explanation:

7 0
3 years ago
You use Cat5e twisted pair cable on your network. Cables are routed through walls and the ceiling. A user puts a screw in the wa
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Answer:

Short circuit describes this condition.

Explanation:

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Consider the following class definitions. public class BClass { private int x; private double y; public void print() { } } publi
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Answer:

dObject will have 2 (two) instance variables.

Explanation:

6 0
3 years ago
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