The answer is B becausePower brakes are a system of hydraulics used to slow down or stop most motor vehicles. It uses a combination of mechanical components to multiply the force applied to the brake pedal by the driver into enough force to actuate thebrakes and stop a vehicle that can weigh several tons.
Answer:
Explanation:
The following piece of code is written in Java. It creates the method as requested that takes in two generic objects and compares them using the .equals() built in Java method. This method will return True if the objects are identical or False if they are not. A test case is used in the code and the output can be seen in the attached image below.
public static <T> boolean comparePerez(T a, T b) {
return a.equals(b);
}
Answer:
<u>First test:</u> Give a list of disordered numbers to the sorting algorithm an examine if the output is correctly sorted.
<u>Second test:</u> Give a list of ordered numbers to the sorting algorithm an analyze if the output is still correctly ordered.
<u>Third test:</u> Give a list of ordered numbers and some non-numeric values to the sorting algorithm and check how is managed the exception in case of error or if the output is correctly ordered.
Answer:
down below
Explanation:
score = input() # gets student's score input
max = input() # gets max number
percent = (score/max)*100 # multiply by a hundred to get percentage
if percent > 52: # checks if percent is greater than 52
print("well dont you have at least a grade 5")
else # if percent is less than or equal to 52 it will print this instead
print("Unlucky, you need to revise more for the next test.")
THIS PART IS NOT CODE:
make sure you indent/tab the print statements or else you'll get an error
Answer:
The program is written using PYTHON SCRIPT below;
N=int(input(" Enter number of Rows you want:"))
M=[] # this for storing the matrix
for i in range(N):
l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))
M.append(l)
print("The 2D Matrix is:\n")
for i in range(N):
print(end="\t")
print(M[i])
W=[] # to store the first non zero elemnt index
T=[] # to store that value is positive or negative
L=len(M[0])
for i in range(N):
for j in range(L):
if (M[i][j]==0):
continue
else:
W.append(j) # If the value is non zero append that postion to position list(W)
if(M[i][j]>0): #For checking it is positive or negative
T.append(+1)
else:
T.append(-1)
break
print()
print("The first Non Zero element List [W] : ",end="")
print(W)
print("Positive or Negative List [T] : ",end="")
print(T)
Explanation:
In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.
It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.
