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liberstina [14]
3 years ago
5

Given the two expressions below: 1) 4x2 − 8x + 9 2) 3x2 + 2y + 6 Is the sum of the two expressions above a polynomial? Why or wh

y not?
Mathematics
1 answer:
Mkey [24]3 years ago
8 0
Sum of polynomials are always polynomials.

Note that despite it's name, single constants, monomials, binomials, trinomials, and expressions with more than three terms are all polynomials.
For example,
0, π sqrt(2)x, 4x+2, x^2+3x+4, x^2-x^2, x^5+x/ π -1
are all polynomials.

What makes an expression NOT a polynomial?
Expressions that contain non-integer or negative powers of variables, rational functions, infinite series.
For example,
sqrt(x+1), 1/x+4, 1+x+ x^2/2!+x^3/3!+x^4/4!+...., (5x+3)/(6x+7)
are NOT polynomials.

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F(x)=3x-8
iVinArrow [24]
What this is asking is for you to plug values into the following function:f(x)=\frac{3x-8}{6x}

Since the question is asking you to find f(3)-f(1), this is how you work it out:
You take the function;
f(x)=\frac{3x-8}{6x}
And plug the numbers indicated in for x;
f(x)=\frac{3x-8}{6x}\\
f(3)=\frac{3(3)-8}{6(3)}\\
f(3)=\frac{9-8}{18}\\
f(3)=\frac{1}{18}\\\\
f(1)=\frac{3(1)-8}{6(1)}\\
f(1)=\frac{3-8}{6}\\
f(1)=\frac{-5}{6}\\\\
Now\ what\ you\ do\ is\ you\ subract\ f(3)\ and\ f(1).\\
f(3)-f(1)\\
f(3)-f(1)=\frac{1}{18}-\frac{-5}{6}\\
f(3)-f(1)=\frac{1}{18}-\frac{-15}{18}\\
f(3)-f(1)=\frac{1+15}{18}\\
f(3)-f(1)=\frac{16}{18}=\frac{8}{9}
So the answer to f(3) - f(1) = \frac{8}{9}
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