<span>given:
increase in inventories= $13
increase in accounts receivable =$29
increase in accounts payable=$17
solution:
change in net working capital = increase in inventories + increase in accounts receivable - increase in accounts payable.
change in net working capital = 13+29-17 = $25</span>
Note the slope intercept form: y = mx + b, in which m = slope
Isolate the y. Note the equal sign, what you do to one side, you do to the other. First, add 3x to both sides
-3x (+3x) + 6y = (+3x) + 12
6y = 3x + 12
Fully isolate the y. Divide 6 from both sides (and to all terms)
(6y)/6 = (3x + 12)/6
y = (3x)/6 + (12)/6
Simplify
y = (1/2)x + 2
y = 0.5x + 2 is your equation.
The slope is direclty left of the x (or the m variable). In this case, it is 0.5
0.5 is your answer (or 1/2 if wanted in fraction form)
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Subject- Math/Geometry
Directions- In order to answer the following question, please use the image below:
Question- What is true about tangent segments AX & BX?
Side Note- Please show all the work on how you came to your answer.(Note- All I want is the work shown with your answer, if you can't explain it then that's fine)
Answer- What’s true about the tangent segments AX and BX are, that they are congruent to each other.
Answer:
F (4, 2) G (2, 2) H (0, -4)
Step-by-step explanation:
Find the next two terms in the given sequence, then write it in recursive form. A.) {7,12,17,22,27,...} B.) { 3,7,15,31,63,...}
iren [92.7K]
Answer:
A) a_n = 5n + 2
B) a_n = (2^(n + 1)) - 1
Step-by-step explanation:
A) The sequence is given as;
{7,12,17,22,27,...}
The differences are:
5,5,5,5.
This is an arithmetic sequence following the formula;
a_n = a_1 + (n - 1)d
d is 5
Thus;
a_n = a_1 + (n - 1)5
Now, a_1 = 7. Thus;
a_n = 7 + 5n - 5
a_n = 5n + 2
B) The sequence is given as;
{ 3,7,15,31,63,...}
Now, let's write out the differences of this sequence:
Differences are:
4, 8, 16, 32
This shows that it is a geometric sequence with a common ratio of 2.
In the given sequence, a_1 = 3 and a_2 = 7 and a_3 = 15
Thus, a_2 = 2a_1 + 1
Also, a_(2 + 1) = 2a_2 + 1
Combining both equations, we can deduce that: a_(n + 1) = 2a_n + 1
Thus; a_n can be expressed as:
a_n = (2^(n + 1)) - 1