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shepuryov [24]
4 years ago
13

Jack earns $90,000 while Priscilla earns $130,000. A regressive social security tax of 5%, paid only up to $90,000, would mean t

hat
(A) Priscilla pays more tax dollars than Jack.
(B) Both pay the same amount of dollars in the tax but Jack pays a lower tax rate.
(C) Both pay the same amount of dollars in the tax and pay the same tax rate.
(D) Both pay the same amount of dollars in the tax even though Jack pays in a higher tax rate bracket.
(E) Priscilla pays no taxes (income over $90,000) so the burden falls on Jack.
Business
1 answer:
Vsevolod [243]4 years ago
5 0

D) Both will pay the same amount of dollars in the tax even though Jack pays in a higher tax bracket.

Explanation:

With the regressive tax system, the higher you earn the lower the tax you are liable to pay.

Since Priscilla earns more that the cap of $90,000 she is liable to pay tax on only the $90,000 and the rest ($130,000-$90,000) $40,000 is exempted from tax.

Whiles Jack is liable to the same tax as Priscilla thought he earns lower than her.

<em>Computations.</em>

Jack: 5% x $90,000 = $4,500

Priscilla: 5% x $90,00 = $4,500

<em>Amount to take home</em>.

Jack: $90,000 - $4,500 = $85,500

Priscilla: $130,000 - $4,500= $125,500

#learnwithbrainly

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Answer:

A. What is the optimal size of the production run for this particular compound?

first we have to determine the holding cost per unit = h = (22% + 012%) x ($3.5) = $1.19 per unit, per year

then we have to calculate the modified holding cost per year = h' = h x [1 / (D/P)] = $1.19 x [1 / (600,000/2,500,000)] = $0.9044 per unit, per year

now we have to substitute h for h' in the EOQ formula:

Q' = √ [(2 x S x D) / h'] = √ [(2 x $1,500 x 600,000) / $0.9044] = 44,612.44 ≈ 44,612 units

B. What proportion of each production cycle consists of uptime and what proportion consists of downtime?

Time between production runs = Q' / D = 44,612 / 600,000 = 0.07435333

Uptime = Q' / P = 44,612 / 2,500,000 = 0.0178448

Downtime = total time - uptime = 0.07435333 - 0.0178448 = 0.05650853

uptime = 0.0178448 / 0.07435333 = 24% of total time

downtime = 0.05650853 / 0.07435333 = 76% of total time

C. What is the average annual cost of holding and setup attributed to this item? If the compound sells for $3.90 per pound, what is the annual profit the company is realizing from this item?

average annual holding cost and setup costs = (AD/Q') + (h'Q'/2) = [($1,500 x 600,000) / 44,612] + [($0.9044 x 44,612) / 2] = $40,144

profit per unit = $3.90 - $3.50 = $0.40 per pound

total annual profit = ($0.40 x 600,000) - $40,144 = $199,856

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The advice is wrong. A sampling error only accounts for the difference in results based on the use of a sample rather than the entire population.

Explanation:

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How can conflicts between the interests of stakeholders be resolved by a corporation's management?
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The Atlanta's cost allocated to Nashville will be $663,500.

Explanation:

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