Question

A pile of sand has a weight of 90kg.

Answer 1

Add the ratios to find the total shares:

2 + 3 +7 = 12

Divide the total weight by the number of shares:

90 kg/ 12 =7.5 kg per share.

Now multiple each share by the weight per share:

Small = 2 x 7.5 = 15 kg

Medium = 3 x 7.5 = 22.5 kg

Large = 7 x 7.5 = 52.5 kg

Answer 2

Total Weight of sand =90Kg

Ratio in which sand is divided= 2:3:7

Let x be the fundamental unit in which the sand is divided.

By conservation of mass.

2x +3x + 7x= 90

=> 12x =90

=> x=90/12 =45/6=15/2=7.5

So Amount of sand in small bag=2×7.5=15Kg

Amount of sand in medium bag =3×(7.5)=23.5Kg

Amount of sand in Large bag =7×(7.5)=52.5 Kg

Hope it helps...

Regards;

Leukonov/Olegion.